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Arada [10]
3 years ago
15

Jimmy is planning his birthday party! He spent $35 on balloons and chocolate cake. He bought balloons that cost $0.25 each and a

chocolate cake for $10. He wrote the equation 0.25x+10=35 to represent the situation. Explain what each piece of the equation represents and why the equation is in that order
Mathematics
1 answer:
emmainna [20.7K]3 years ago
5 0

In the equation, x represents the number of balloons. We say that 25 cents per balloon becomes 0.25x.

Jimmy also purchased a chocolate cake. This is the PLUS sign in the equation.

The total for everything purchased is $35.

Balloons x at 25 cents each = 0.25x plus a chocolate cake for $10 together equals $35.

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Answer: The answer is 300 gallons.

Step-by-step explanation: Riemann sum is a method of calculating the total  area under a curve on a graph, which is also known as Integral.

To calculate that area, we divide it into a number of rectangles with one point touching the curve. The curve has a closed interval [a,b] that can be subdivided into n subintervals, each having a width of Δx_{k} = \frac{b-a}{n}

If a function is defined on the closed interval [a,b] and c_{k} is any point in [x_{k-1},x_{k}], then a Riemann Sum is defined as ∑f(c_{k})Δx_{k}.

For this question:

Δx_{k} = \frac{7-0}{5} = 1.4

Now, we have to find s(t) for each valor on the interval:

s(t) = 0.29t^{2} - t +25

s(0) = 25

s(1) = 24.29

s(2) = 24.16

s(3) = 24.61

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s(7) = 32.21

Now, using the formula:

∑f(c_{k})Δx_{k} = 1.4(25+24.29+24.16+24.61+25.64+29.44+32.21)

∑f(c_{k})Δx_{k} = 1.4(212.6)

∑f(c_{k})Δx_{k} ≅ 300

With Riemann Sum, it is estimated the total country's per capita sales of bottled water is 300 gallons.

3 0
3 years ago
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timofeeve [1]

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8 0
3 years ago
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Answer:

The amount earned is $327.75

Step-by-step explanation:

If the workwr working for 5h gets $71.25, then his working for 1 hour could be said to be x.

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1h = x; cross multiplying would result in

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3 years ago
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You invest $2,800 in an account that<br> pays an interest rate of 5.5%,<br> compounded continuously.
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