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ale4655 [162]
3 years ago
14

PLZ I NEED HELP, LAST QUESTION ! ! ! :,D

Mathematics
1 answer:
pantera1 [17]3 years ago
5 0

Step-by-step explanation:

s(n) = 2n - 5  

                  What is the sum  1st and 6th terms of the sequence?  12

s(1) = 2(1) - 5           =   -3

s(2) = 2(2) - 5         =   -1

s(3) = 2(3) - 5         =    1

s(4) = 2(4) - 5         =   3

s(5) = 2(5) - 5         =   5

s(6) = 2(6) - 5         =   7       add these numbers

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How do u do b??????????
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the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6  = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output  of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5

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cause the parabola is horizontal and opens on the right.

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