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3 years ago

How do you find the rate of change in a graph

Mathematics

2 answers:

Anni [7]3 years ago

6 0

To find the unit rate, divide the numerator and denominator of the given rate by the denominator of the given rate

mario62 [17]3 years ago

5 0

if the function of the graph is given differentiate the function to get the expression for the rate of change(or slope).

else, draw a tangent to any required pont and find the gradient or slope.

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What is the equation of the line that is parallel to y-3x=2 and that passes through (6,1)?

Artemon [7]

Try this solution (analytic method):

1. if new line is parallel to the given one (y=3x+2) it means the new line has a form y=3x+b, where b - number.

2. In order to calculate 'b', it need to substitute the coordinates of point (6;1) into the equation of the new line:

1=3*6+b, ⇒ b=-17.

3. If to make up the equation of the new line:

y=3x-17

Answer: A

8 0

3 years ago

The graph of a quadratic function contains (4,-64) and it's vertex is at the origin.write an equation for this function.

lesya692 [45]

Answer:

Step-by-step explanation:

Not sure what form you need this in, but it really doesn't matter, as you'll see in the final equation. I used the vertex form and solved for a:

$y=a(x-h)^2+k$

We are given the vertex (h, k) as the origin (0, 0), and we have a point that the graph goes through as (4, -64). That's our x and y. Plugging in what we have:

$-64=a(4-0)^2+0$ gives us

-64 = 16a and

a = -4. That means that the quadratic equation is

$y=-4x^2$ which is both vertex form and standard form here, no difference.

5 0

3 years ago

I need help!

timama [110]

Fractions,rats, and percents all interconnect. For ext,50%=11/2 =1:2

6 0

3 years ago

Read 2 more answers

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

This implies that they go on round after $11\frac{2}{3}\ min$

4 0

3 years ago

The figure below is a rhombus. z = [?]

Nonamiya [84]

Answer:

28 degrees

Step-by-step explanation:

z and x are the same. Do the math.

3 0

3 years ago