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Evgen [1.6K]
3 years ago
9

How do you find the rate of change in a graph

Mathematics
2 answers:
Anni [7]3 years ago
6 0
To find the unit rate, divide the numerator and denominator of the given rate by the denominator of the given rate
mario62 [17]3 years ago
5 0

if the function of the graph is given differentiate the function to get the expression for the rate of change(or slope).

else, draw a tangent to any required pont and find the gradient or slope.


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Circle B has a radius of 7.2in. Find the diameter of circle B dilated by a factor of 8.1
Helen [10]
Since the scale factor is greater than 1, this dilation will be an enlargement. Therefore, you multiply 7.2 times 8.1 to get 58.32. This question asks for diameter, so multiply 58.32 times 2 to get 116.64 in.
5 0
2 years ago
If their food and beverages costs$25.30 and there is an 8% meals tax, how much is the bill
Mashutka [201]
Hey there Unrazed90,

Answer : 

100% = $25.30
1% = $25.30 / 100
      = $0.253
8% = $0.253 x 8 
      = $2.024
Total = $25.30 + $2.024
         = $27.324
         = $27

Hope this helps :D

<em>~Natasha ♥</em>
8 0
3 years ago
7. A restaurant owner wants to see if there is a relationship between the amount of
Harman [31]

Answer:

a) Yes, the two variables correlated

b) Yes, variation of sugar changes the number of orders for item containing sugar

Step-by-step explanation:

a) Yes the two variables are moderately co-related as the value of co-relation lies between 0.5 and 0.7

b) Yes the variation in amount of sugar leads to variation in the number of orders with sugar.

8 0
2 years ago
This really hard help please
bonufazy [111]

Answer:

is it 4.8, I don't really know

8 0
3 years ago
insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of
ss7ja [257]

Answer: (13.22\%,\ 19.34\%)

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : \hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628

=16.28\%

Significance level : \alpha= 1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

Confidence level for population proportion:-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= (13.22\%,\ 19.34\%)

7 0
3 years ago
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