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eduard
3 years ago
11

State the postulate or theorem you would use to prove each pair of triangles congruent.

Mathematics
1 answer:
gogolik [260]3 years ago
8 0

Answer:

Not possible

Step-by-step explanation:

The only information we are given are the pairs of angles that are congruent which is not enough information to prove that they are congruent

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Determine if the following infinite series converges or diverges
Mandarinka [93]

Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.

<h3>How do we verify if a sequence converges of diverges?</h3>

Suppose an infinity sequence defined by:

\sum_{k = 0}^{\infty} f(k)

Then we have to calculate the following limit:

\lim_{k \rightarrow \infty} f(k)

If the <u>limit goes to infinity</u>, the sequence diverges, otherwise it converges.

In this problem, the function that defines the sequence is:

f(k) = \frac{k^3}{k^4 + 10}

Hence the limit is:

\lim_{k \rightarrow \infty} f(k) = \lim_{k \rightarrow \infty} \frac{k^3}{k^4 + 10} = \lim_{k \rightarrow \infty} \frac{k^3}{k^4} = \lim_{k \rightarrow \infty} \frac{1}{k} = \frac{1}{\infty} = 0

Hence, the infinite sequence converges, as the limit does not go to infinity.

More can be learned about convergent sequences at brainly.com/question/6635869

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6 0
2 years ago
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What is the length of the diagonal of a poster board with dimensions 22 inches by 28 inches? Round to the nearest tenth.
devlian [24]

Answer:

The length of the diagonal of a poster board is 35.6\ in

Step-by-step explanation:

Let

x----> the length of the diagonal of a poster board

we know that

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x^{2}=22^{2}+28^{2} \\ \\x^{2}=1,268\\ \\x=35.6\ in

4 0
3 years ago
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Select all of the potential solution(s) of the equation 2log5x = log54.
Vanyuwa [196]

Answer:

x = ±2

Step-by-step explanation:

A equation is given to us , which is ,

\longrightarrow 2log_5(x) = log_5 4

From <u>properties </u><u>of </u><u>logarithm </u>we know that ,

\longrightarrow alog\ m = log \ m^a

Applying this to LHS , we have ;

\longrightarrow log_5 x^2 = log_5 4

Now the bases of logarithm on LHS and RHS is same . On comparing , we have ;

\longrightarrow x^2 = 4

Put square root on both sides,

\longrightarrow x =\sqrt{4}

Simplify ,

\longrightarrow \underline{\underline{ x =\pm 2 }}

This is the required answer.

6 0
3 years ago
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