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wel
3 years ago
15

A plane flew 360km in 3 hrs when flying with the wind.With no change in the wind,the return trip took 4 hrs.Find the speed of th

e wind and the speed of the plane
Mathematics
1 answer:
morpeh [17]3 years ago
6 0
Speed of the plane: 250 mph
Speed of the wind: 50 mph
Explanation:
Let p = the speed of the plane
and w = the speed of the wind
It takes the plane 3 hours to go 600 miles when against the headwind and 2 hours to go 600 miles with the headwind. So we set up a system of equations.
600
m
i
3
h
r
=
p
−
w
600
m
i
2
h
r
=
p
+
w
Solving for the left sides we get:
200mph = p - w
300mph = p + w
Now solve for one variable in either equation. I'll solve for x in the first equation:
200mph = p - w
Add w to both sides:
p = 200mph + w
Now we can substitute the x that we found in the first equation into the second equation so we can solve for w:
300mph = (200mph + w) + w
Combine like terms:
300mph = 200mph + 2w
Subtract 200mph on both sides:
100mph = 2w
Divide by 2:
50mph = w
So the speed of the wind is 50mph.
Now plug the value we just found back in to either equation to find the speed of the plane, I'll plug it into the first equation:
200mph = p - 50mph
Add 50mph on both sides:
250mph = p
So the speed of the plane in still air is 250mph.
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Test the given claim. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, and then state the concl
Firlakuza [10]

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Being π1: proportion of passenger cars with only rear plates, and π2: proportion of commercial trucks with only rear plates, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2

The test statistic is z=-1.895.

The P-value is 0.029.

The P-value (0.03) is bigger than the significance level (0.01), so the effect is not significant. The null hypothesis failed to be rejected.

There is no enough evidence to claim that commercial trucks owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

Step-by-step explanation:

The claim is that commercial trucks owners violate laws requiring front license plates at a higher rate than owners of passenger cars. We have to test the hypotheses on the difference between proportions.

Being π1: proportion of passenger cars with only rear plates, and π2: proportion of commercial trucks with only rear plates, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2

The significance level is 0.01.

The passenger cars, with a sample size n1=2135, have a proportion of:

p_1=x_1/N_1=244/2135=0.114

The commercial trucks, with a sample size n2=339, have a proportion of:

p_2=x_2/N_2=51/339=0.150

The weighted proportion, needed to estimate the standard error, is calculated as:

p=\dfrac{x_1+x_2}{N_1+N_2}=\dfrac{244+51}{2135+339}=\dfrac{295}{2474}=0.119

The standard error for the difference between proportions can be calculated as:

\sigma=\sqrt{\dfrac{p(1-p)}{N_1}+\dfrac{p(1-p)}{N_2}}=\sqrt{\dfrac{0.119*0.881}{2135}+\dfrac{0.119*0.881}{339}}\\\\\\\sigma=\sqrt{ 0.00036 }= 0.019

Then, the z-statistic is:

z=\dfrac{p_1-p_2}{\sigma}=\dfrac{0.114-0.150}{0.019}=\dfrac{-0.036}{0.019}=  -1.895

The P-value for this left tailed test is:

P-value=P(z

The P-value (0.03) is bigger than the significance level (0.01), so the effect is not significant. The null hypothesis failed to be rejected.

There is no enough evidence to claim that commercial trucks owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

6 0
3 years ago
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