Speed of the plane: 250 mph Speed of the wind: 50 mph Explanation: Let p = the speed of the plane and w = the speed of the wind It takes the plane 3 hours to go 600 miles when against the headwind and 2 hours to go 600 miles with the headwind. So we set up a system of equations. 600 m i 3 h r = p − w 600 m i 2 h r = p + w Solving for the left sides we get: 200mph = p - w 300mph = p + w Now solve for one variable in either equation. I'll solve for x in the first equation: 200mph = p - w Add w to both sides: p = 200mph + w Now we can substitute the x that we found in the first equation into the second equation so we can solve for w: 300mph = (200mph + w) + w Combine like terms: 300mph = 200mph + 2w Subtract 200mph on both sides: 100mph = 2w Divide by 2: 50mph = w So the speed of the wind is 50mph. Now plug the value we just found back in to either equation to find the speed of the plane, I'll plug it into the first equation: 200mph = p - 50mph Add 50mph on both sides: 250mph = p So the speed of the plane in still air is 250mph.
Each cylindrical shell has radius (the horizontal distance from the axis of revolution to the curve ); has height (the vertical distance between a point on the -axis in and the curve ).
