Ask question

Ask question

All categories

3 years ago

7

A(n) ______ series ranks an element according to its ease with which it undergoes certain chemical reactions. reaction action so

lubility activity replacement

1 answer:

Andrews [41]3 years ago

3 0

Reaction i think . . . . . . . . . . . . . .

You might be interested in

What volume of ethylene glycol (C2H6O2), a nonelectrolyte, must be added to 11.0 L of water to produce an antifreeze solution wi

shusha [124]

Answer:

The volume of ethylene glycol, we must add is 8.2 L

Explanation:

Let's apply the formula for the colligative property of Depression of freezing point, to solve this

ΔT = Kf . m . i

Where ΔT = Fussion T° in pure solvent - Fussion T° in solution

Kf = Cryoscopic constant (equal to 1.86 °C kg/mol for the freezing point of water)

m = molality (mol of solute in 1kg of solvent)

i = The number of ions dissolved in solution. As it is a non-electrolytic compound, the i values 1 (Van't Hoff factor)

0°C - (-25°C) = 1.86 kg°C/mol . m

25°C / 1.86 m/kg°C = m

13.4 = mol/kg

As water density is 1 g/ml, let's convert firstly 11L in mL

11L .1000 = 11000mL

In conclusion, we have 11000 g of water.

density = mass / volume

So, if we have 13.4 moles in 1 kg of water, how many moles of ethylene glycol do we have, in 11000 g of water.

11000 g = 11kg

1 kg _____ 13.4 moles of ethylene glycol

11 kg _____ (11 . 13.4)/1 = 147.4 moles

Molar mass of ethylene glycol = 62.07 g/m

Moles . molar mass = mass

147.4 m . 62.07g/m = 9149.1 g

Now we can apply density of ethylene glycol to find out the volume

Density ethylene glycol = ethylene glycol mass / ethylene glycol volume

1.11 g/ml = 9149.1 g / ethylene glycol volume

ethylene glycol volume = 9149.1 g/ 1.11 g/ml

ethylene glycol volume = 8242 mL

8242 mL = 8.2 L

8 0

4 years ago

the slowest step in a reaction mechanism requires the collision represented above to occur. Which of the following most likely i

Zielflug [23.3K]

Answer:

D. The catalyst could absorb one of the particles, making a successful (reaction-producing) collision with the other particles more likely.

Explanation:

The way that a solid (heterogenous) catalysts functions is by the reactant getting adsorbed to the surface of the catalyst at active sites. An interaction between the surface of the catalyst and the reactant makes the reactants more reactive, causing the reaction to happen.

7 0

2 years ago

how would the rate of diffusion change if the po2 in the capillaries was 40 mmhg and the po2 in the muscle cell changed from 40

BlackZzzverrR [31]

The rate of diffusion change would increase if the PO₂ in the capillaries was 40 mmHg and the PO₂ in the muscle cell changed from 40 to 20 mmHg.

Simple diffusion is the movement of molecular substances from a region of higher concentration to lower concentration. The mechanism with which the movement of O₂ travels from the blood to the body tissues takes place with the use of simple diffusion.

Now, if PO₂ changes from 40 → 20 mmHg in the muscle cells, and the PO₂ in the blood = 40mmHg. It implies that the pressure gradient(P) has increased. As such, there is an increase in the rate of diffusion of oxygen from the blood to muscle cells.

Learn more about diffusion here:

brainly.com/question/14392880?referrer=searchResults

6 0

2 years ago

Hydrochloric acid is widely used as a laboratory reagent in refining ore for the production of tin and tantalum, and as a cataly

Lyrx [107]

<u>Answer: </u>0.0285 moles of HCl is present in given amount of solution.

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}$ .....(1)

Given values:

Molarity of HCl = 0.453 M

Volume of solution = 62.85 mL

Putting values in equation 1, we get:

$0.453mol/L=\frac{\text{Moles of HCl}\times 1000}{62.85}\\\\\text{Moles of HCl}=\frac{0.453\times 62.85}{1000}=0.0285moles$

Hence, 0.0285 moles of HCl is present in given amount of solution.

4 0

3 years ago

Which compound contains both sigma and pi bonds

Misha Larkins [42]

Any compound with multiple covalent bonds

6 0

3 years ago

Read 2 more answers