Answer:
Approximately 
.
Explanation:
<h3>Number of moles of formula units of magnesium sulfate required to make the solution</h3>
The unit of concentration in this question is "
". That's equivalent to "
" (moles per liter.) In other words:
.
However, the unit of the volume of this solution is in milliliters. Convert that unit to liters:
.
Calculate the number of moles of 
formula units required to make this solution:
.
<h3>Mass of magnesium sulfate in the solution</h3>
Look up the relative atomic mass data of 
, 
, and 
on a modern periodic table:
Calculate the formula mass of using these values:
.
Using this formula mass, calculate the mass of that (approximately) 
of formula units:
.
Therefore, the mass of required to make this solution would be approximately .
The subscripts tell the ratio of one element to another in a
compound. In this case, there are 4 P atoms per 10 O atoms. This could also be
interpreted as 4 mol P per 10 mol O. Therefore:
Mol P = (38.5 mol P4O10)/(4 mol P/ 1 mol P4O10) = 154 mol P
Explanation:
We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.
Next we will calculate how many moles of 
are present in 85.00 mL of 1.500 M sulfuric acid.
As, Molarity = 
1.500 M = 
n = 0.1275 mol
Now set up and solve a stoichiometric conversion from moles of to grams of 
. As, the molar mass of is 84.01 g/mol.
= 21.42 g
So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.
NH3 = water (it is actually a water soluble gas)
C6H14 = CCl4 (C6H14 won't mix with water at all)
Na2S = water (Na2S is a salt. Salts dissolve best in water)
Br2 = CCl4, but it will also dissolve in water.
Answer:Metals are an excellent conductor of electricity and heat because the atoms in the metals form a matrix through which outer electrons can move freely. Instead of orbiting their respective atoms, they form a sea of electrons that surround the positive nuclei of the interacting metal ions.
Explanation:
.
.
.