Be sure to answer all parts. Sulfonation of benzene has the following mechanism: (1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3 [fast] (2) SO3
+ C6H6 → H(C6H5+)SO3− [slow] (3) H(C6H5+)SO3− + HSO4− → C6H5SO3− + H2SO4 [fast] (4) C6H5SO3− + H3O+ → C6H5SO3H + H2O [fast] (a) Write the overall equation for this reaction. (b) Write the overall rate law for the initial rate of the reaction. Rate =
1 answer:
Answer:
C6H6 + H2SO4 ---> C6H5SO3H + H2O
k [H2SO4]^2 [C6H6]
Explanation:
In writing the rate equation for a reaction, all the steps in the reaction sequence are summed and transient intermediates are taken into consideration.
Writing rate equation began at the slowest step as shown in the image attached to this answer below. This is because the slowest step determines the rate of reaction. Concentration of intermediates are usually expressed in terms of concentration of reactants as intermediates do not enter the rate equation.
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The question is incomplete, here is the complete question:
Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine.
at 1,000 K
Calculate Kc for the reaction
<u>Answer:</u> The value of for the final reaction is
<u>Explanation:</u>
The given chemical equations follows:
We need to calculate the equilibrium constant for the equation, which is:
As, the final reaction is the twice of the initial equation. So, the equilibrium constant for the final reaction will be the square of the initial equilibrium constant.
The value of equilibrium constant for net reaction is:
We are given:
Putting values in above equation, we get:
Hence, the value of for the final reaction is