Be sure to answer all parts. Sulfonation of benzene has the following mechanism: (1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3 [fast] (2) SO3
+ C6H6 → H(C6H5+)SO3− [slow] (3) H(C6H5+)SO3− + HSO4− → C6H5SO3− + H2SO4 [fast] (4) C6H5SO3− + H3O+ → C6H5SO3H + H2O [fast] (a) Write the overall equation for this reaction. (b) Write the overall rate law for the initial rate of the reaction. Rate =
1 answer:
Answer:
C6H6 + H2SO4 ---> C6H5SO3H + H2O
k [H2SO4]^2 [C6H6]
Explanation:
In writing the rate equation for a reaction, all the steps in the reaction sequence are summed and transient intermediates are taken into consideration.
Writing rate equation began at the slowest step as shown in the image attached to this answer below. This is because the slowest step determines the rate of reaction. Concentration of intermediates are usually expressed in terms of concentration of reactants as intermediates do not enter the rate equation.
You might be interested in
Answer: Photoelectric is characterized by or involving the emission of electrons from a surface by the action of light.
Photoelectric effect is the emission of electrons when a radiation of frequency higher than the threshold frequency falls on the surface of an element. The substance which undergoes photoelectric effect is called as photoelectric.
Ground state is the state representing the lowest energy state.
Excited state is the state which represents a high energy state.
An electron in ground state absorbs energy to move to the excited state.
