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ella [17]
3 years ago
12

A line intersects the point (-11,4)and has a slope of -2. What are the inputs to the point -slope formula?

Mathematics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

The inputs to this formula are:

  • The x-coordinate of the point: x_0 = -11;
  • The y-coordinate of the point: y_0 = 4; and
  • The slope of the line: m = -2.

The equation of this line in point-slope form will be:

y - 4 = -2(x +11).

Step-by-step explanation:

The general form of a 2D line in its point-slope form is:

l:\; y - y_0 = m(x - x_0).

This form of the equation of a line takes two pieces of information:

  • The x-y coordinate of a point on the line (x_0, y_0), and
  • The slope (a.k.a. gradient) of that line.

For this line, the point (x_0, y_0) is (-11, 4).

  • x_0 = -11, and
  • y_0 = 4.

The slope of this line is -2. In other words,

  • m = -2.

Apply the point-slope formula for a 2D line:

l:\; y - 4 = -2 (x - (-11)).

l:\; y - 4 = -2 (x +11 ).

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3 years ago
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diamong [38]

Answer:

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Step-by-step explanation:

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Therefore the focus is (1,5)

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The real numbers $x$ and $y$ are such that \begin{align*} x + y &= 4, \\ x^2 + y^2 &= 22, \\ x^4 &= y^4 - 176 \sqrt{
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The left side is a difference of squares, and we get another difference of squares upon factoring. We end up with

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