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Tamiku [17]
2 years ago
15

Need help asap bc I don’t understand this. I’m not trying to fail. Been on this lesson for 30+ min

Mathematics
1 answer:
Nitella [24]2 years ago
7 0

Answer:

75 in²

Step-by-step explanation:

From the diagram, you can see that the shape is made up of a square and 4 triangles. (We know it's a square as the width = length).

First, find the area of the square.

Area of a square = width x length = 5 x 5 = 25 in²

All the triangles are the same, so we need to find the area of one of the triangle and multiply it by 4.

Area of a triangle = \frac{1}{2} x base x height = \frac{1}{2} x 5 x 5 = 12.5 in²

So total area of 4 of these triangles = 4 x 12.5 = 50 in²

Therefore the total surface area = 25 + 50 = 75 in²

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2/3 is equivalent to?
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4/6 6/9 40/60 the first one is mulitied by two third one is multiplied by three and the fourth one is multiplied by 20
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To save at least $15,000 in 5 years, which monthly deposit is the minimum amount an eighth grader and his family should plan to
sergejj [24]

Answer:

C $250

Step-by-step explanation:

based on the question we can get the equation

where m = money, the years are converted to months

15000 = 60m

divide by 60 to each side

m= 250

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3 years ago
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Write 7/14 • (-7/12) in lowest terms
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The final answer should be -49/168.
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What is the probability that all the roots of x2 + bx + c = 0 are real? [0,1]?
notsponge [240]

x^2+bx+c will have real roots when the discriminant of the quadratic, \Delta=b^2-4c, is non-negative, i.e.

b^2-4c\ge0\implies b^2\ge4c

Your question about probability is currently impossible to answer without knowing exactly what the experiment is. Are you picking b,c at random from some interval? Is the choice of either distributed a certain way?

I'll assume the inclusion of "[0,1]" in your question is a suggestion that both b,c are chosen indepently of one another from [0, 1]. Let B,C denote the random variables that take on the values of b,c, respectively. I'll assume B,C are identical and follow the standard uniform distribution, i.e. they each have the same PDF and CDF as below:

f_X(x)=\begin{cases}1&\text{for }0

F_X(x)=\begin{cases}0&\text{for }x

where X is either of B,C.

Then the question is to find P(B^2\ge4C). We have

P(B^2\ge4C)=P\left(C\le\dfrac{B^2}4\right)

and we can condition the random variable C on the event of B=b by supposing

P\left(C\le\dfrac{B^2}4\right)=P\left(\left(C\le\dfrac{B^2}4\right)\land(B=b)\right)=P\left(C\le\dfrac{B^2}4\mid B=b\right)\cdot P(B=b)

then integrate over all possible values of b.

=\displaystyle\int_{-\infty}^\infty P\left(C\le\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_{-\infty}^\infty F_C\left(\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_0^1\dfrac{b^2}4\,\mathrm db=\frac1{12}

4 0
3 years ago
A rectangular lot is 140 meters long and 100 meters wide. Give the length and width of another rectangular lot that has the same
mr Goodwill [35]

Step-by-step explanation:

Length of rectangle is 140 m and its breadth is 100 m

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For rectangle, P = 2(l+b)

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For a rectangle, A = lb

A = 140 × 100

A = 14000 m²

We need to write the length and breadth such that it has the same perimeter but a larger area.

Let the length is 110 m and breadth is 130 m.

Perimeter, P = 2(110+130)

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Perimeter is same as previous

Area, A = 110 × 130

A =  14300 m²

Area is more than the initial area.

Hence, this is the required solution.

4 0
3 years ago
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