U write it as 1/6+1/6+1/6+1/6=4/6
Given the slope, m = -2/3, and the x-intercept, (3,0):
Use these values and plug into the slope-intercept form to solve for the y-intercept, b:
y = mx + b
0 = -2/3(3) + b
0 = -2 + b
Add 2 to both sides to isolate b:
0 + 2 = -2 + 2 + b
2 = b
Now that we have our slope, m = -2/3, and the y-intercept, 2
The linear equation in slope-intercept form is:
y = -2/3x + 2
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Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to

.

---> equation (1)
By using pythagoras rule which states that the

---> equation (2)
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,

substitute this value in equation (1) then

where A is the area of the square whose side is x
Answer:
The answer is (d) ⇒ eccentricity = 6 , hyperbola , directrix x = 3/2
Step-by-step explanation:
∵ r = ek/(1 ± ecosФ)
∵ r = 9/(1 + 6cosФ)
∴ e = 6 ⇒ eccentricity = 6
∵ e > 1
∴ The conic is hyperbola
∵ ek = 9
∴ k = 9/6 = 3/2
∴ The directrix x = 3/2
The answer I believe is the second one to the top