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Debora [2.8K]
3 years ago
12

HELP!!!

Mathematics
1 answer:
Anna35 [415]3 years ago
3 0

Answer:

see below

Step-by-step explanation:

shape LNMP is :

  • translated as 0,-7
  • flip of mirrored along y-axis
  • reflected imaged is ABCD as given
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tapes-r-us is have a sale on hq tape players. The regular price is $60. The discount is $18. What percent discount is this?
olga nikolaevna [1]

The discount is 30%

Step-by-step explanation:

Given

Price of tape = $60

Discount = $18

In order to find the percentage, we will use the percentage formula

Percentage = \frac{discount}{Price}*100\\= \frac{18}{60} *100\\=0.3 * 100\\= 30\%

Hence,

The discount is 30%

Keywords: Percent, sale

Learn more about percentage at:

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#LearnwithBrainly

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2 years ago
Can someone help me?It's urgent and thank you!
lidiya [134]

Answer:

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Step-by-step explanation:

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Determine if the relationships are linear and if so are they proportional
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8 0
2 years ago
A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
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