3 years ago

V1 - 2 sin cos 0 = cos 0 - sin

1 answer:

kramer3 years ago

4 0

$\sqrt{1 - 2sin θ \cosθ } = \sqrt{ {sin}^{2} θ + {cos}^{2}θ - 2 sinθcosθ } = \sqrt{ {(cosθ - sinθ) }^{2} } = cosθ - sinθ$

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V1 - 2 sin cos 0 = cos 0 - sin​

V1 - 2 sin cos 0 = cos 0 - sin