V1 - 2 sin cos 0 = cos 0 - sin

1 answer:

kramer3 years ago

4 0

$\sqrt{1 - 2sin θ \cosθ } = \sqrt{ {sin}^{2} θ + {cos}^{2}θ - 2 sinθcosθ } = \sqrt{ {(cosθ - sinθ) }^{2} } = cosθ - sinθ$

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Vadim26 [7]

Answer:

1/2

Step-by-step explanation:

slope = $\frac{y_{2}-y_{1} }{x_{2}-x_{1}}$

(0-(-4))/(0-(-8)) = 1/2

7 0

3 years ago

algol [13]

110y+10=340

Subtract 10 from both sides

110y=330

Divide by 110 to get variable on its own

110y/110=330/110

y=3

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3 years ago

Kitty [74]

X=16log i’m guessing not sure:)

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3 years ago

Free_Kalibri [48]

I think
8+10=18
just place 1 before 0

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3 years ago

pshichka [43]

Answer:

it is an interior alternate angle and x= 27

Step-by-step explanation:

5 0

3 years ago

V1 - 2 sin cos 0 = cos 0 - sin​