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solmaris [256]
3 years ago
13

V1 - 2 sin cos 0 = cos 0 - sin​

Mathematics
1 answer:
kramer3 years ago
4 0

\sqrt{1 -  2sin θ \cosθ }  =  \sqrt{ {sin}^{2} θ   + {cos}^{2}θ  -  2 sinθcosθ } =  \sqrt{ {(cosθ   - sinθ) }^{2} }  = cosθ - sinθ

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nydimaria [60]
Well, let's say we start with 10 granola bars.
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