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podryga [215]
3 years ago
8

How do you solve an equation like this 2+x=16-3+4

Mathematics
1 answer:
denis-greek [22]3 years ago
5 0

Answer:

Q.2+x=16-3+4

or,2+x=17

or,x=17-2

or,x=15...ans

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Rewrite the expression c + 0.25c using fractions instead of decimal numbers.
gogolik [260]

Answer:

\huge\boxed{\frac{5c}{4},\ or\ c+\frac{1}{4}c,\ or\ c+\frac{c}{4}}

Step-by-step explanation:

The decimal 0.25 can simply be converted into a fraction by putting it over 100.  

0.25 = \frac{25}{100}

Then, simply divide both the numerator and denominator by 25 to get

\frac{25/25}{100/25}, or \frac{1}{4}

Hope it helps :)

8 0
3 years ago
The table shows a linear relationship between x and y.
Mama L [17]

Answer:

В:

X 3 9 15      

Y 4 16 20

6 0
3 years ago
If you could help I would really appreciate it, but if not that’s fine. Thank you.
Simora [160]

Answer:

Option C is correct answer.

Step-by-step explanation:

We need to draw the graph of piece wise function

f(x)\[ \begin{cases}       -2-x & if\:x\leq 1 \\      -3+2x & if\: x>1   \end{cases}\]

So, for drawing the graph, we will find values of f(x) for both the given equations.

First finding f(x) for -2-x \:\: if\:x\leq1

The value of x must be less than or equal 1

x       f(x)

1        -3

0       -2

-1       -1

-2       0

-3       1

-4       2

The graph will start from closed circle because x ≤ 1

Now, finding values of f(x) for -3+2x\: if\:x>1

The value of x must be greater than 1

x        f(x)

2        1

3        3

4        5

5        7

The graph will start from open circle because x> 1

Now, plotting these numbers we will get graph of Option C.

Option C is correct answer.

4 0
3 years ago
A process is operating at 0.15 fraction nonconforming. We desire to catch a shift to 0.19 fraction nonconforming on the fraction
Lena [83]

Answer:

Sample size>=  743

Step-by-step explanation:

7 0
3 years ago
Can someone help me plz
iris [78.8K]

SIMPLIFY TO A SINGLE POWER OF 6:

\dfrac{6^5}{6} = \dfrac{6^5}{6^1} = 6^{5-1} = 6^4

5 0
3 years ago
Read 2 more answers
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