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3 years ago

7

A triangle has one angle that measures 11 degrees, one angle that measures 47 degrees, and one angle that measures 122 degrees.

What kind of triangle is it?

1 answer:

agasfer [191]3 years ago

8 0

Answer:

obtuse

Step-by-step explanation:

The largest angle is more than 90°, so the triangle is called an "obtuse" triangle.

Here are the classifications based on the measure of the largest angle:

< 90° -- acute triangle

= 90° -- right triangle

> 90° -- obtuse triangle . . . . . like the one in this problem statement

You might be interested in

Solve for x and please roundddd

kati45 [8]

Should be 37 degrees

We know the lengths of the adjacent and opposite sides when looking at the angle x, so we use those two sides to find the trig ratio.

So we use Opposite/adjacent (Tangent) Which is 54/72=0.75

Now we get out the trig ratio table. Because we used the tangent ratio (O/A) , we use that column to look for the closest number to 0.75.
The closest is 0.754, and the degree for it is 37 degrees

Rlly hope this helps :)))

6 0

2 years ago

Read 2 more answers

One coin in a collection of 65 has two heads. The rest are fair. If a coin, chosen at random from the lot and then tossed, turns

geniusboy [140]

Answer:

P=1/65.

Step-by-step explanation:

We knaow that one coin in a collection of 65 has two heads. If a coin, chosen at random from the lot and then tossed, turns up heads 6 times in a row. We calculate the probability that it is the two-headed coin.

We calculate the number of possible combinations:

$C_1^{65}=\frac{65!}{1!(65-1)!}=65$

Number of favorable combinations is 1.

Therefore, the probability is

P=1/65.

6 0

3 years ago

The area of a rectangle is 6x^2-9x-15. And the length is (2x-5). Which expression best represents the rectangle’s width?

tester [92]

<h2><u>AnswEr :</u> </h2>

The area of the rectangle is of the form 6x² - 9x - 15

Factoring the given expression,

$\sf \: {6x}^{2} - 9x - 15 \\ \\ \leadsto \: \sf \: 3\bigg( {2x}^{2} - 3x - 5 \bigg) \\ \\ \leadsto \: \sf \: 3 \bigg( {2x}^{2} - 5x + 2x - 5 \bigg) \\ \\ \leadsto \: \sf \: 3 \bigg((2x - 5)(x + 1) \bigg)$

Length of the rectangle is 2x - 5

Thus,

$\leadsto \: \sf \: (2x - 5)(3x + 3)$

<h3>The breadth of the rectangle is 3x + 3 </h3>

4 0

3 years ago

The length of ZX is 2 units. What is the perimeter of triangle XYZ?

dezoksy [38]

Keywords

triangle,perimeter,distance, length, side, points

we know that

The <u>perimeter</u> of a<u> triangle</u> is the sum of the three <u>length</u> <u>side</u>

To find the<u> length</u> <u>side</u> calculate the <u>distance</u> between two <u>points</u>

The formula to calculate the <u>distance</u> between to <u>points</u> is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step 1

Find the <u>distance</u> ZY

$Z(1,0)\\Y(3,1)$

substitute the values

$d=\sqrt{(1-0)^{2}+(3-1)^{2}}$

$dZY=\sqrt{5}\ units$

Step 2

Find the <u>distance</u> XY

$X(-1,4)\\Y(3,1)$

substitute the values

$d=\sqrt{(1-4)^{2}+(3+1)^{2}}$

$dXY=\sqrt{25}=5\ units$

Step 3

Find the <u>perimeter</u> of the <u>triangle</u>

$P=ZX+ZY+XY$

we have

$dZX=2\sqrt{5}\ units$

$dZY=\sqrt{5}\ units$

$dXY=5\ units$

Substitute

$P=(2\sqrt{5}+\sqrt{5}+5)\ units$

therefore

the answer is

$P=(3\sqrt{5}+5)\ units$

4 0

3 years ago

Read 2 more answers

Find the missing lengths of the sides.

Anarel [89]

Given:

The figure of a right angle triangle.

$a=b$

Hypotenuse = $9\sqrt{2}$ in.

To find:

The missing lengths of the sides.

Solution:

In the given right angle triangle both legs a and b are equal, and hypotenuse is $9\sqrt{2}$ in.

Using Pythagoras theorem, we get

$Hyponteuse^2=Base^2+Perpendicular^2$

$(9\sqrt{2})^2=(a)^2+(b)^2$

$81(2)=(a)^2+(a)^2$ $[\because a=b]$

$81(2)=2(a)^2$

Divide both sides by 2.

$81=(a)^2$

Taking square root on both sides.

$\pm \sqrt{81}=a$

$\pm 9=a$

Side cannot be negative. So,

$9=a$

Thus, the missing side lengths are a=9 in and b=9 in.

Therefore, the correct option is C.

6 0

3 years ago