The angles of a pentagon are x, x − 5 0 , x + 100 , 2x + 150and 2x + 300 . Find all the angles.
1 answer:
Answer:
The interior angles are 70°,65°,80°,155° and 170°
Step-by-step explanation:
step 1
Find the sum of the interior angles of the pentagon
The sum is equal to
S=(n-2)*180°
where
n is the number of sides of polygon
n=5 (pentagon)
substitute
S=(5-2)*180°=540°
step 2
Find the value of x
Sum the given angles and equate to 540
x+(x-5)+(x+10)+(2x+15)+(2x+30)=540°
7x+50=540°
7x=490°
x=70°
step 3
Find all the angles
x=70°
(x-5)=(70-5)=65°
(x+10)=(70+10)=80°
(2x+15)=(2*70+15)=155°
(2x+30)=(2*70+30)=170°
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