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3 years ago

Explain how this is wrong or right please thanks

Mathematics

2 answers:

tensa zangetsu [6.8K]3 years ago

5 0

Im Pretty sure you got it right. because what i did was get random numbers and tried to equal it to the numbers such as 15, 16, and 17. Have a good day and ask questions!!

-Kaylie

Nezavi [6.7K]3 years ago

3 0

You got them right:)

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Hannah plays bejeweled. She said that there are 28,036 daily users playing bejeweled and that number is 10 times less than the a

Virty [35]

Answer:

If your trying to find the amount of daily users playing FarmVille, it would be 280,360 daily users

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2 years ago

If 3x = 7y, what are the following ratios?<br> 3y:x

Orlov [11]

for

: To do this we must divide each side of the equation by

which will give us

while keeping the equation balance.

8 0

3 years ago

Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye

svetlana [45]

Answer:

The required recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

$Year \: 1 = 500$

Each year thereafter the number of leaves was 40% more than the year before so that means

$Year \: 2 = 500(1+0.40) = 500\times 1.4\\$

For the third year the number of leaves increase 40% than the year before so that means

$Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\$

Similarly for fourth year,

$Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\$

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

$f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330$

So there will be 10330 leaves in the 10th year.

3 0

3 years ago

Read 2 more answers

Given sin x =-4/5 and x is in quadrent 3, what is the value of tan x/2

4vir4ik [10]

Answer:

We can write sin x in terms of tan x/2 using the formula:

⇒ sin x = (2 tan (x/2)) / (1 + tan2(x/2))

Therefore, using the above formula, we can find the values of tan x/2 by putting the value of sin x.

⇒ -4/5 = (2 tan (x/2)) / (1 + tan2(x/2))

Now, if we replace tan (x/2) by y, we get a quadratic equation:

⇒ 0.8y2 + 2y + 0.8 = 0

⇒ 2y2 + 5y + 2 = 0

By using the quadratic formula, we get y = -0.5, -2

Hence, the value of tan (x/2) = -0.5, -2

Now, we have two solutions of tan (x/2).

Now, let's check for the ideal solution using the formula tan x = (2 tan (x/2)) / (1 - tan2(x/2)).

For tan (x/2) = -0.5:

⇒ tan x = 2(-0.5) / 1 - (-0.5)2 = -4/3

It is also given that x lies in the third quadrant. We know that tan is positive in the third quadrant, and here we get tan x = -4/3 which is negative.

Hence, we can say that tan (x/2) = -0.5 is not a correct solution. Hence it is rejected.

Now let's check for tan (x/2) = -2.

⇒ tan x = 2(-2) / 1 - (-2)2 = 4/3

Here, we get tan x = 4/3 which is positive.

Hence, we can say that tan (x/2) = -2 is a correct solution.

5 0

3 years ago

2 vertical buildings are 42 metres apart and the shorter building is 135m high. The angle of elevation from the top of the short

ipn [44]

Answer:

Step-by-step explanation:

base=42 m

height=h=?

base angle θ=60°

tan 60=h/42

h=42tan 60=42√3≈72.75 m

height of taller building=135+42√3 m≈135+72.75≈207.75 m≈208 m

6 0

3 years ago