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Sav [38]
3 years ago
7

How to solve proportion using cross products,k8=14/4

Mathematics
1 answer:
luda_lava [24]3 years ago
6 0
Multiply the variable k times 4 would give you 4k.
Then cross multiply 14x8 = 112

Therefore, you would have 4k = 112.
Divide 112 by 4 to get your answer!
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Currently, each student in our school system is assigned a 6-digit (each
N76 [4]

Answer:

26,000,000 codes

Step-by-step explanation:

To find how many unique codes can be created, we just need to check how many possibilities there are for each letter or digit in the code.

Each letter has 26 possible values, and each digit has 10 possible values, so as we have 1 letter and 6 digits, the total number of unique codes are:

26 * 10 * 10 * 10 * 10 * 10 * 10 = 26,000,000 codes.

6 0
3 years ago
What is 2/6 x 3/9 i need help
Ira Lisetskai [31]

Answer:1/9

Step-by-step explanation:

Simplified:

1/3 x 1/3

1/9

3 0
3 years ago
Read 2 more answers
Plz help and show work! easy points! It needs factored​
Bad White [126]

Answer: 2(x2 + 10x + 16)

Step-by-step explanation: You need to factor the whole equation by 2. In other words divide each term by 2 and put parentheses to indicate factoring. You should get 2(x2 + 10x + 16)

4 0
3 years ago
Read 2 more answers
What is the answer of:<br><img src="https://tex.z-dn.net/?f=2%20%5Cdiv%203%20%20%2B%20%20%5Csqrt%7B5%7D%20" id="TexFormula1" tit
pshichka [43]

Answer:

\frac{2  \: +  \: 3 \sqrt{5} }{3}

Step-by-step explanation:

\frac{2}{3}  +  \sqrt{5}  =

= \frac{2}{3}  + ( \sqrt{5}   \times  \frac{3}{3} )

= \frac{2}{3}  +  \frac{3 \sqrt{5} }{3}

=  \frac{2  \: +  \: 3 \sqrt{5} }{3}

4 0
2 years ago
n 2000 the population of a small village was 2,400. With an annual growth rate of approximately 1.68%, compounded continuously,
Nitella [24]

Answer:

The population would be 3358

Step-by-step explanation:

Since, exponential growth function if the growth is compound continuously,

A = Pe^{rt}

Where,

P = initial population,

r = growth rate per period,

t = number of periods,

Given,

The population in 2000, P = 2,400,

Growth rate per year = 1.68% = 0.0168,

Number of years from 2000 to 2020, t = 20,

Thus, the population in 2020,

A=2400 e^{0.0168\times 20}

=2400 e^{0.336}

= 3358.4136

\approx 3358

6 0
3 years ago
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