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3 years ago

Find the derivative of f(x) = -2x2 + 11x at x = 9.

Mathematics

1 answer:

Marianna [84]3 years ago

8 0

Answer:

The value of the derivative at x = 9 is -25

Step-by-step explanation:

Here in this question, we are told to find the derivative of the given equation at the point where x = 9

What we need to do here is simply, differentiate f(x), then substitute that value x = 9 into the differentiated equation

In notation form, what we are to find is f’(9)

So;

f(x) = -2x^2 + 11x

f’(x) = -4x + 11

So therefore;

f’(9) = -4(9) + 11

f’(9) = -36 + 11

f’(9) = 11-36

f’(9) = -25

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Determine whether the given signal is a solution to the difference equation. Then find the general solution to the difference eq

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The answer to this question can be defined as follows:

Step-by-step explanation:

The given equation is:

$y_{k + 2} + 8y_{k +1} - 9y_{k} = 20k + 12..(1)$

put,

$y_k = k^2\\\\y_{k+2}=(k+2)^2\\\\y_{k+1}=(k+1)^2\\\\$

$(k+2)^2+8(K+1)^2-9k^2 = 20k+12\\\\=20k+12= 20K+12\\\\$

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Now,

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the symbol form is:

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$\to m^2+8m-9=0\\\\\to m^2+(9-1)m-9=0\\\\\to m^2+9m-m-9=0\\\\\to m(m+9)-(m+9)=0\\\\\to (m+9)(m-1)=0\\\\\to m=-9 \ \ \ \ \ \ \ m=1\\$

The general solution is:

$y_k = c_1(-9)^k + c_2(`1)^k\\\\y_k =c_1(-9)^k+c_2$

The complete solution is:

$y_k=(y_k)_c+(y_k)_y\\\\y_k= c_1(-9)^k+c_2+k^2$

The answer is option b: $y_k = k^2 + c_1(-9)^k + c_2$

After solve the complete solution is:

$\bold{y_1=c_1(-9)^k+c_2+k^2.....}$

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