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Alex777 [14]
3 years ago
6

Expand each binomial. (2y-z)^5​

Mathematics
1 answer:
Stels [109]3 years ago
6 0

(2y-z)^5=(2y-z)^2\cdot(2y-z)^3 \\(4y^2-4yz+z^2)\cdot(8y^3-12y^2+6yz-(-z)^3) \\(4y^2-4yz+z^2)\cdot(8y^3-12y^2+6yz-z) \\\boxed{32y^5-48y^4+24y^3z-4y^2z-32y^4z+48y^3z-24y^2z^2+4yz^2+8y^3z^2-12y^2z^2+6yz^3-z^3} \\

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