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Norma-Jean [14]
3 years ago
11

What is the difference of the two polynomials?

Mathematics
2 answers:
guapka [62]3 years ago
7 0

Simplify

9x^2 + 8x - (2x^2 + 3x)

Simplify brackets

9x^2 + 8x - 2x^2 - 3x

Collect like terms

(9x^2 - 2x^2) + (8x - 3x)

Simplify

<u>7x^2 + 5x</u>

<u>Answer: A. 7x2 + 5x</u>

Ganezh [65]3 years ago
5 0

Answer:

a) 7x^2 + 5x

Step-by-step explanation:

(9x^2 + 8x) – (2x^2 + 3x)

Distribute the minus sign

(9x^2 + 8x) – 2x^2 - 3x

Line them up vertically

  (9x^2 + 8x)

– 2x^2 - 3x

-------------------

7x^2     +5x

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If m∠NOP = 24° and m∠NOQ = 110°, what is m∠POQ?
andrew11 [14]

Correct answer for the above question is - option B. 86°

<u>Step-by-step explanation:</u>

Given:

∠NOP = 24°

∠NOQ = 110°

∠NOP and ∠POQ are adjacent angles

To Find:

∠POQ = ?

Solution:

Hereby, we can say that ∠POQ lies between line OQ and ON as given (∠NOP and ∠POQ are adjacent angles )

∠NOQ - ∠NOP = ∠POQ

∠POQ = 110° - 24°

<u>∠POQ = 86°</u>

Angle POQ is  86°

Thus we can conclude option B as correct answer.

4 0
3 years ago
A ball is thrown into the air. The height in feet of the ball can be modeled by the equation h = -16t2 + 20t + 6 where t is the
makkiz [27]

f(t)=h=-16t^2+20t+6&#10;&#10;

a=-16, b=20, c =6

Δ=b^2-4ac=20^2-4*(-16)*6=400+384=784

\sqrt{Δ}=\sqrt{784}=28

max:

p=-\frac{b}{2a}=-\frac{20}{-32}=\frac{20}{32}=\frac{5}{8}

max heigh: h=-16(\frac{5}{8})^2+20*\frac{5}{8}+6=-16\frac{25}{64}+\frac{100}{8}+6

h=-\frac{25}{4}+\frac{50}{4}+6=\frac{-25+50+24}{4}=\frac{49}{4}

h=\frac{49}{4} at t=\frac{5}{8}s


will fall down at t:

t=\frac{-20-28}{-32}=\frac{-48}{-32}=\frac{3}{2}=1.5

t=1.5s

8 0
3 years ago
Explain how you would show 135% on a 10-by10 grid
dangina [55]
You would shade in 135 of the squares in the grid(s)
8 0
3 years ago
A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100


Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n


now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605

Hence answer is approx 1606 beetles will be there after 20 years.


Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549

Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n

33.174666862=n

Hence answer is approx 33 years.

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!!
diamong [38]
DE. AB, is going up BC, isn't decreasing or increasing. CD, isn't decreasing or increasing. Therefore your answer is DE.
8 0
3 years ago
Read 2 more answers
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