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patriot [66]
3 years ago
13

PLEASE HELP !!

Mathematics
1 answer:
Burka [1]3 years ago
6 0
The answer would be, B. (2,0)
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Shankar has decided to train to be a Carbucks Barrista. Being young and inexperienced, for every order he makes a mistake in mak
astra-53 [7]

Answer:

Step-by-step explanation:

Since each trial is independent of the other

no of mistakes he does is binomial with p = 1/3

a) the probability that he makes no mistakes on his first 10 orders but the 11th order is a mistake

= (\frac{2}{3}) ^{10} *\frac{1}{3}\\=\frac{2^{10} }{3^{11} }

b) Prob that shanker quits = P(Shankar does I one mistake and Fran does not do the first one)+Prob (Shanker does mistake in the II one while Fran does both right)

= \frac{1*5}{3*6} +\frac{2}{3} \frac{1}{3}(\frac{5}{6})^2  =\frac{5}{18} +\frac{50}{216} \\=\frac{55}{108}

6 0
3 years ago
Jorge's hourly salary is $7.65. last week he worked 23 hour week how much did he earn
lions [1.4K]
$7.65 × 23 = $175.95

Answer: $175.95
6 0
3 years ago
36 is the same as _____ radians.
Over [174]
The formula is (degree)x(pi÷180)
36 x pi ÷ 180
0.63 rad
6 0
3 years ago
Read 2 more answers
In a right angle,the altitude to a 6ft hypotenuse.Find the length of the altitude and each leg.
Nuetrik [128]

Answer:a=3.6 and b=4.8

Step-by-step explanation:(a^2)+(b^2)=(c^2)

Where c is hypotenuse is equal to 6. A right triangle is also known as a 3,4,5 triangle where the 2 legs are 3 and 4 and hypotenuse is 5. Find the factor in size difference by dividing your hypotenuse of 6 by the hypotenuse of 5 you get 1.2. Now multiply the 3 and 4 by 1 2 to get your answers of 3.6 and 4.8.

To check work simply plug in your legs as a and b

(3.6^2)+(4.8^2)=(6^2)

(12.96)+(23.04)=(36)

6 0
3 years ago
HELPP!!
SSSSS [86.1K]

Answer:

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

7 0
3 years ago
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