What’s the approximate circumference of a circle with radius 10 feet?
2 answers:
Approximate circumference of circle is feet that is 62.8 feet.
<u>Solution :</u>
Need to determine approximate circumference of a circle with radius as 10 feet.
So given that radius of circle = 10 feet
Circumference of circle is product of constant with radius of circle r.
=> Circumference of circle =
On substituting the value of radius, we get circumference
So circumference of a circle of radius 10 feet =
Taking = 3.14, we get circumference = 20 x 3.14 = 62.8 feet
Hence approximate circumference of circle is feet that is 62.8 feet.
You might be interested in
Answer:
Where 0 < x < 3
The location of the local minimum, is (2, 0)
The location of the local maximum is at (0, 16)
Step-by-step explanation:
The given function is f(x) = (x + 2)⁴
The range of the minimum = 0 < x < 3
At a local minimum/maximum values, we have;
∴ (-x + 2)³ = 0
x = 2
When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2
We have, f(2) = (-2 + 2)⁴ = 0
The location of the local minimum, is (2, 0)
Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3
When x = 0, -x + 2 = 0 + 2 = 2
Similarly, we have;
-x + 2 = 1, when x = 1
-x + 2 = 0, when x = 2
-x + 2 = -1, when x = 3
Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16
The location of the local maximum is at (0, 16).
<u>Answer</u>:
<em>I'm bad at explaining this but after this, go to sleepppp</em>
<u>Step-by-step explanation:</u>
<u />
