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natita [175]
3 years ago
14

The ages of two groups of dance students are shown in the following dot plots: A dot plot shows Age in years on the horizontal a

xis. For Group X, there are 3 dots on 4, 1 dot on 5, 5 dots on 8, 2 dots on 10, 3 dots on 12, and 2 dots on 16. For Group Y, there are 2 dot on 5, 3 dots on 7, 1 dot on 9, 3 dots on 11, 1 dot on 13, 2 dots on 14, 1 dot on 15, 1 dot on 18, 3 dots on 20, 1 dot on 22, and 2 dots on 24. The mean absolute deviation (MAD) for group X is 3.07 and the MAD for group Y is 5.25.
Which of the following observations can be made using these data?
Group X has less variability in the data.
Group X has greater variability in the data.
Group Y has a lower range.
Group Y has a lower mean.
Mathematics
2 answers:
Dimas [21]3 years ago
4 0

Answer:Group X has less variability in the data.


Step-by-step explanation:


lutik1710 [3]3 years ago
3 0
I did the test. The answer is "Group X has less variability in the data."
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Is -6 greater than -17
lions [1.4K]
no -17 is greater than -6
4 0
3 years ago
Read 2 more answers
Rationalize the denominator and simplify 6/√2-√3
ss7ja [257]
Answer:

<span>=3<span>√6</span>−3<span>√5</span></span>

Explanation:

<span>3<span><span>√5</span>+<span>√6</span></span></span>

We rationalise the denominator by multiplying the expression by the conjugate of the denominator. <span><span>√5</span>−<span>√6</span></span>

<span><span>3⋅<span>(<span>√5</span>−<span>√6</span>)</span></span><span><span>(<span>√5</span>+<span>√6</span>)</span>⋅<span>(<span>√5</span>−<span>√6</span>)</span></span></span>

<span>=<span><span>3⋅<span>(<span>√5</span>)</span>+3⋅<span>(−<span>√6</span>)</span></span><span><span>(<span>√5</span>+<span>√6</span>)</span>⋅<span>(<span>√5</span>−<span>√6</span>)</span></span></span></span>

<span>=<span><span>3<span>√5</span>−3<span>√6</span></span><span><span>(<span>√5</span>+<span>√6</span>)</span>⋅<span>(<span>√5</span>−<span>√6</span>)</span></span></span></span>

<span>Applying identity
<span><span>(a+b)</span><span>(a−b)</span>=<span>a2</span>−<span>b2</span></span> to the denominator.</span>

<span>=<span><span>3<span>√5</span>−3<span>√6</span></span><span><span><span>(<span>√5</span>)</span>2</span>−<span><span>(<span>√6</span>)</span>2</span></span></span></span>

<span>=<span><span>3<span>√5</span>−3<span>√6</span></span><span>5−6</span></span></span>

<span>=<span><span>3<span>√5</span>−3<span>√6</span></span><span>−1</span></span></span>

<span>=−3<span>√5</span>+3<span>√6</span></span>

<span>=3<span>√6</span>−3<span>√<span>5
</span></span></span>

5 0
3 years ago
Find the slope of the given points (3, 4) and (7,-4).<br> A)-1/2<br> B) 2<br> C) -2<br> D) 0
kakasveta [241]

Answer:

-2

Step-by-step explanation:

y = kx + n

When you insert the given points you get

3k + n = 4 \\

7k + n =  - 4 \\

Than you multiply the first one by - 1 and sum it with the second to get rid of n

4k =  - 8 \\ k =  - 2

7 0
3 years ago
The speed of a baseball pitcher’s fastball is 92.4 miles per hour. His fastball is 10% faster than his curveball. How fast is th
12345 [234]

Answer:

Step-by-step explanation:

101.64

4 0
3 years ago
Find the minimum and maximum values of the function subject to the given constraint. (if an answer does not exist, enter dne.) f
nata0808 [166]
Via Lagrange multipliers:

L(x,y,\lambd)=x^2y+x+y+\lambda(xy-5)
L_x=2xy+1+\lambda y=0
L_y=x^2+1+\lambda x=0
L_\lambda=xy-5=0

\underbrace{10}_{2xy}+1+\lambda y=0\implies \lambda=-\dfrac{11}y
xy=5\implies y=\dfrac5x\implies\lambda=-\dfrac{11}5x

\impliesx^2+1+\left(-\dfrac{11}5x\right)x=0\implies x^2=\dfrac56\implies x=\pm\sqrt{\dfrac56}
xy=5\implies y=\pm\sqrt{30}

At these points, we get local minima of f\left(\pm\sqrt{\dfrac56},\pm\sqrt{30}\right)=\pm2\sqrt{30}.

- - -

Another way to do this is to make f(x,y) a function independent of y, which is made possible by the constraint.

xy=5\implies y=\dfrac5x
\implies f(x,y)=f\left(x,\dfrac5x\right)=F(x)=6x+\dfrac5x
\implies F'(x)=6-\dfrac5{x^2}=0\implies x=\pm\sqrt{\dfrac56}

and so on.
8 0
3 years ago
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