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Oliga [24]
3 years ago
6

What shows the equation 12x +4y=140 in general form

Mathematics
1 answer:
baherus [9]3 years ago
3 0
If general form means y=mx+b form then your answer would be B
You might be interested in
Find the geometric mean of the pair of numbers
Svetach [21]

Answer: a. 55

Step-by-step explanation:

The formula to find the geometeric mean between two numbers a and b is given by :-

G.M. =\sqrt{ab}

The given numbers are : 275 and 11

The geometric mean of 275 and 11 is given by :-

G.M.=\sqrt{275\times11}\\\\\Rightarrow\ G.M. =\sqrt{3025}\\\\\Rightarrow\ G.M.=\sqrt{55\times55}\\\\\Rightarrow\ G.M.=\sqrt{55^2}\\\\\Rightarrow\ G.M.=55

Hence, the geometric mean of 275 and 11 is 55.

So , the correct option is a. 55 .

4 0
3 years ago
HELP ASAP
Alexxandr [17]

Answer: A − 9/7

Step-by-step explanation:

Hi, to answer this question we have to convert all the numbers into decimal form.

-3 1/3 = - (3x3+1)/3 =-10/3 = - 3.3334

-4/5 = -0.8

Since he number must greater than −3 1/3 but less than − 4/5.

−3 1/3 < x < − 4/5.

- 3.3334 < x < -0.8

The correct option is A = -9/7 , because in decimal form is equal to -1.28-

- 3.3334 < -1.28 < -0.8

5 0
3 years ago
❤️❤️making sure I chose the right one❤️
KengaRu [80]
Yes, angle B and angle D are equal, so it is true
6 0
3 years ago
Read 2 more answers
Nathaniel had a bag of 5 green marbles,3 blue marbles,6 red marbles,and 6 yellow marbles.Find the probability if Nathaniel pulls
Dovator [93]
To find probability, you'd have to find the total number of marbles (5+3+6+6=20), and since there are 3 blue marbles, the probability of picking one is 3 out of 20, or 3/20
If that blue marble isn't replaced, there will then be 19 marbles, and 2 blue ones. So the probability of him picking another blue marble is 2/19
8 0
3 years ago
Please help me on this problem
Anna71 [15]

Answer:

The pairs of integer having two real solution forax^{2} -6x+c = 0 are

  1. a = -4, c = 5
  2. a = 1, c = 6
  3. a = 2, c = 3
  4. a = 3, c = 3

Step-by-step explanation:

Given

ax^{2} -6x+c = 0

Now we will solve the equation by putting all the 6 pairs so we get the  following

-3x^{2} -6x-5 = 0 for a = -3 , c=-5

-4x^{2} -6x+5 = 0 for a = -4 , c=5

1x^{2} -6x+6 = 0 for a = 1 , c=6

2x^{2} -6x+3 = 0 for a = 2 , c=3

3x^{2} -6x+3 = 0 for a = 3 , c=3

5x^{2} -6x+4 = 0 for a = 5 , c=4

The above  all are Quadratic equations inn general form ax^{2} +bx+c=0

where we have a,b and c constant values

So for a real Solution we must have

Disciminant , b^{2} -4\timesa\timesc \geq 0

for a = -3 , c=-5 we have

Discriminant =-24 which is less than 0 ∴ not a real solution.

for a = -4 , c=5 we have

Discriminant = 116 which is greater than 0 ∴ a real solution.

for a = 1 , c=6 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 2 , c=3 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 3 , c=3 we have

Discriminant =0 which is equal to 0 ∴ a real solution.

for a = 5 , c=4 we have

Discriminant =-44 which is less than 0 ∴ not a real solution.

7 0
3 years ago
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