Answer:
304.89m
Explanation:
Given
acceleration a = 2.52m/s²
final speed v = 39.2m/s
initial speed = 0m/s (car accelerates from rest)
Using the equation of motion below to get the distance of Doc brown from Marty;
v² = u²+2as
substitute the given parameters
39.2² = 0²+2(2.52)s
1536.64 = 0+5.04s
divide both sides by 5.04
1536.64/5.04 = 5.04s/5.04
rearrange the equation
5.04s/5.04 = 1536.64/5.04
s = 304.89m
Hence He and Marty must stand at 304.89m to allow the car to accelerate from rest to a speed of 39.2 m/s?
Answer:
magnitude of gravitational force between the Earth and the Sun at B is greater than that at A
Explanation:
Formula of gravitational force:
F = GMm/r^2
(r is the distance between 2 objects)
We see that r(B) < r(A) since at B, the Earth is closer to the Sun than at A
According to the Formula, the smaller r is, the greater F is
So, F(B) > F(A)
You can try recalling and rehearsing information about the memory.
