Answer:
The value is 
Explanation:
From the question we are told that
The mass of the car is 
The acceleration is 
Generally the net force applied on the rope is mathematically represented as
Here W is the weight of the car which is evaluated as
=> 
=> 
Generally the net force can also be mathematically represented as
So
=> 
=>
Answer:
The formula for force according to Newton's second law of motion is F=ma or force for an object to move is equal to mass times acceleration.
Acceleration or average acceleration defined as change in velocity per time.
F=ma
F=1.2x10³kg*(20m/s)(1/5s)=4.8x10³ Newtons
Explanation:
fthat's not the answer then i'm sorry
Answer:
The group that remains unaltered is called the control group.
1) Balanced
2) Not balanced
3) Not balanced
4) Balanced
Answer:
The trucker should drive at a speed of 11 m/s m/s
Explanation:
mass of the small car, m₁ = 795 kg
initial velocity of the small car, u₁ = 35 m/s(due east)
Mass of the truck, m₂ = 3360 kg
Initial velocity of the truck, u₂ = ?
Final velocity, V = u₁ sin37 ( the line between the camera and the collision makes an angle 37° with respect to the north)
According to the law of momentum conservation:
For the x -component
m₁u₁ = (m₁ + m₂)Vsinθ
m₁u₁ = (m₁ + m₂)Vsin37
(795*35) = (795 + 3360)* Vsin37
27825 = 2500.54V
V = 27825/2500.54
V = 11.13 m/s
For the y - component
m₂u₂ = (m₁ + m₂)Vcos37
3360*u₂ = (795+3360)*11.13*cos37
3360*u₂ =36933.02
u₂ = 36933.02/3360
u₂ = 11 m/s
