1. What is the skydiver's acceleration?
Initially, like any falling object, a skydiver's downward acceleration is 9.8 meters/seconds^2, or about 28-35 feet per second squared. This acceleration reduces over a few seconds and approaches zero as the skydiver reaches terminal velocity.
Answer:
Contact forces are forces that require the actual contact (touching) of two pieces of matter. There are a variety of contact forces. A very common one is friction. Anytime that two surfaces are in contact with one another, there is friction between the two surfaces. A field force is a force that works at a distance. No touching is required. Gravity is a good example of a field force, because it works whether or not an object is touching something or touching nothing at all.
Answer:
There are 5 of 'em.
It's so amazing.
1. The electric eel; It can generate about 370-650 volts of electric current from it's body.
2. The electric catfish!
About 350-450volts of electric current.
3. The electric Ray.
Say no more. It can generate about 37-220volts.
4. The electric stargazer (really stargazer, lol, and you live down the sea)
About 50volts
and
5. Skate.
Just 4volts.
You know more than to be careful when you go diving in the sea.
I love your question btw. I learnt also.
Answer:
R' = R/2
Therefore, the new resistance of the wire is twice the value of the initial resistance.
Explanation:
Consider a wire with:
Resistance = R
Length = L
Area = A = πr²
where, r = radius
ρ = resistivity
Then:
R = ρL/A
R = ρL/πr² --------------- equation 1
Now, the new wire has:
Resistance = R'
Resistivity = ρ
Length = L' = 2 L
Radius = r' = 2r
Area = πr'² = π(2r)² = 4πr²
Therefore,
R' = ρL'/πr'²
R' = ρ(2 L)/4πr²
R' = (1/2)(ρL/πr²)
using equation 1:
<u>R' = R/2</u>
<u>Therefore, the new resistance of the wire is twice the value of the initial resistance.</u>
