The net force on a 0.50-cm-diameter eardrum is mathematically given as
F= 0.76969 N
<h3>What is the net force on a 0.50-cm-diameter eardrum?</h3>
Generally, the equation for Pressure is mathematically given as
P = ρgh
Therefore
P= 1000*9.8*4
P= 39200 Pa
Where
A= pi*(0.005/2)^2
Generally, the equation for Net force is mathematically given as
F = PA
F= 39200 *( pi*(0.005/2)^2)
F= 0.76969 N
In conclusion, The net force is
F= 0.76969 N
Read more about Pressure
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Answer:
c. probablistic view of nature.
Explanation:
According to the problem of particle in a box in one dimension. If the particle energy E is taken less than the height of the barrier V.
Then with the help of classical mechanics it can be prove that the particle can not cross the barrier but according to the quantum mechanics, there is a small but a finite probability to cross the barrier.
Therefore by the above discussion it can be concluded that quantum mechanics can be thought as a probablistic view of nature.
Answer:
this is for the ppl who delete my answer
suck 8--
Explanation:
The distance from the horizontal top surface of the cube to the water level is "6.282 cm".
<h3>What is Archimedes' principle?</h3>
According to Archimedes' principle, the weight of the fluid that the body displaces is equal to the upward buoyant force that is applied to a body submerged in a fluid, whether fully or partially. The Archimedes' principle is a fundamental physical law in fluid mechanics. It was created by Syracuse's Archimedes.
According to Archimedes' principle, a body submerged in a fluid experiences an upward force proportional to the weight of the fluid that has been displaced. One of the prerequisites for equilibrium is this. We believe that the buoyancy force, also known as the centre of buoyancy, is situated in the middle of the submerged hull.
From Archimedes' principle, we get



=11.72cm
So,
The distance from horizontal top to the water level will be:
=18-11.72
=6.282cm
To learn more about Archimedes' principle refer to:
brainly.com/question/1155674
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The correct answer is
<span>C) -10.7 m/s
In fact, the first rock is moving upward with velocity +4.5 m/s, while the second rock is moving downward with velocity -6.2 m/s, with respect to a fixed reference frame. In the reference frame of the first rock, instead, the second rock is moving with velocity equal to its velocity in the fixed frame minus the velocity of the reference frame of the first rock:
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