Answer:
![\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D)
Step-by-step explanation:
We are required to simplify the quotient: ![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D)
Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:
![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}} =\sqrt[3]{\dfrac{60} {20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D%20%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B60%7D%20%7B20%7D%7D)
![=\sqrt[3]{3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%7D)
The simplified form of the given quotient is .
Answer:
QR = 65.4 m
Step-by-step explanation:
a. Apply Law of Cosines to find QR:
p² = q² + r² - 2qr × Cos P
p = QR = ?
q = PR = 150 m
r = PQ = 120 m
P = 25°
Plug in the values
p² = 150² + 120² - (2)(150)(120) × Cos(25°)
p² = 22,500 + 14,400 - 36,000 × 0.9063
p² = 36,900 - 32,626.8
p² = 4,273.2
p = √4,273.2
p ≈ 65.4 m (nearest tenth)
QR = 65.4 m
Answer:
Please Find the answer below
Step-by-step explanation:
Domain : It these to values of x , for which we have some value of y on the graph. Hence in order to determine the Domain from the graph, we have to determine , if there is any value / values for which we do not have any y coordinate. If there are some, then we delete them from the set of Real numbers and that would be our Domain.
Range : It these to values of y , which are as mapped to some value of x in the graph. Hence in order to determine the Range from the graph, we have to determine , if there is any value / values on y axis for which we do not have any x coordinate mapped to it. If there are some, then we delete them from the set of Real numbers and that would be our Range .
Answer:
-8(7y-8)-3(7y-7)−8(7y−8)−3(7y−7)
Distribute to remove the parentheses.
Collect like terms
-154y+170
Step-by-step explanation:
Answer: 2 is the maximum number of gigabytes
Step-by-step explanation:
