Answer: It's easy and simple!
Step-by-step explanation: Split it into rectangles and multiply the height and length. Than add it together and Then you have your answer.
Well costheta=1, at 0, 2pi,...
knowing this we can exclude the first two as the are not undefined anywhere.
tan is sin/cos, at 0 sin is also 0 so it becomes 0/1 which is 0, not undefined.
sec is1/cos, cos is 1, this is just 1
csc is 1/sin, sin is 0, 1/0 is undefined, meaning there will be an asymptote
cot is cos/sin, this is again 1/0, so it is also an asymptote
The last two answers are the ones you want
Answer:
Step-by-step explanation:
Simplifying
5(4x + p) = w
Reorder the terms:
5(p + 4x) = w
(p * 5 + 4x * 5) = w
(5p + 20x) = w
Solving
5p + 20x = w
Solving for variable 'p'.
Move all terms containing p to the left, all other terms to the right.
Add '-20x' to each side of the equation.
5p + 20x + -20x = w + -20x
Combine like terms: 20x + -20x = 0
5p + 0 = w + -20x
5p = w + -20x
Divide each side by '5'.
p = 0.2w + -4x
Simplifying
p = 0.2w + -4x
<h3>
Answer: 1960 </h3>
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Explanation:
Order doesn't matter when it comes to committees without rankings. Each person on the committee is of equal rank to anyone else. This means we'll use a combination instead of a permutation.
We have 8 men and 3 seats to fill for the men. Plug n = 8 and r = 3 into the nCr combination formula
n C r = (n!)/(r!(n-r)!)
8 C 3 = (8!)/(3!*(8-3)!)
8 C 3 = (8!)/(3!*5!)
8 C 3 = (8*7*6*5*4*3*2*1)/((3*2*1)*(5*4*3*2*1))
8 C 3 = (40320)/((6)*(120))
8 C 3 = (40320)/(720)
8 C 3 = 56
This means there are 56 ways to select the three men from a pool of eight.
Through similar steps, you should plug n = 7 and r = 3 into the nCr combination formula to get 7 C 3 = 35. This means there are 35 ways to pick the three women from a pool of seven.
Overall, there are 56*35 = 1960 ways to select the entire committee of 3 men and 3 women (from a pool of 8 men and 7 women).
2.3423234e+18 man omg lmaaoooo
