The cost of the electricity if 42000 kWh of electricity is used is ; $1680
<h3>Determine the cost of electricity </h3>
<u>Given that ;</u>
value of electricity used = 42000 kWh
cost rate of electricity = $0.04/kWh
Final step : Determine the total cost of electricty used
unit cost = $0.04/kWh
Totals cost = unit cost * value of electricity used
= 0.04 * 42000 = $1680
Hence we can conclude that The cost of the electricity if 42000 kWh of electricity is used is ; $1680.
Learn more about Electricity cost : brainly.com/question/14277272
Answer:
your mom mooching off of me
Explanation:
THE ANSWER IS: <u><em>Make a model</em></u>
Different scientific questions and hypotheses require different types of scientific investigations. Some questions can be answered through controlled experiments. Other questions can be answered through collecting specimens, building models, and/or making observations.
For example, questions about events that occur over thousands of years are best studied through models.
Answer: The colour of A before the starch test is GREEN while after the starch test is BLUE- BLACK. The equation for photosynthesis is
6CO2 + 6H2O → C6H12O6 + 6O2.
Explanation:
PHOTOSYNTHESIS is the process by which green plants use energy from sunlight to manufacture their own food. It is a building up process since simple inorganic compounds such as carbondioxide and water are built up into large organic compounds such as glucose and OXYGEN is given off as a by product.
Oxygen given out in photosynthesis occurs in the light stage during the process of photolysis of water. This occurs when the chlorophyll traps, absorbs and captures light energy and become energised. The energised chlorophyll supplies energy which is to split molecules of water into hydrogen ion ( H+) and hydroxyl ion ( OH-). The hydroxyl ion is reconverted to water and oxygen is given out as a by product.
To show that chlorophyll is NECESSARY for photosynthesis, a variegated leaf with green and yellow patches is used for an experiment.
The green portion is marked A and the yellow portion marked B. The leaf is tested for starch using the procedure below:
--> place leaf in boiling water for half a minute to kill it.
--> decolorize leaf by placing it in hot alcohol.
--> dip decolorize leaf in hot water to soften it.
--> place leaf on tile and add iodine solution to it.
RESULT: It would be found that only the green parts contain starch as blue+black colouration is observed while yellow area is unaffected by iodine.
Answer:
It is A
Explanation:
I had this question on my test last week.
