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4 years ago

Given the function defined, find the average rate of change please

Mathematics

1 answer:

irinina [24]4 years ago

5 0

Rate of change=slope
f(x)=y
z=x

59-58/0-3= -1/3
ANSWER: -1/3

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А(-9, -5), b(6, 5), C(-2, 5)

Rainbow [258]

Answer:

See below

Step-by-step explanation:

Equation: y = $-\frac{2x^2}{21} + \frac{8x}{21} + \frac{43}{7}$

Slope-intercept form: $y = \frac{2}{3} x + 1$

Point slope form: $y + 5 = \frac{10}{7} * (x+9)$

8 0

2 years ago

Mr.Nowlings garden has a length that is 7ft more than twice the width. Draw a diagram to represent this situation.Label each sid

mart [117]

The expression for the perimeter would be

2(x) + 2(2x+7)

which can be simplified to 2x+4x+14

which equals 6x+14

8 0

3 years ago

Read 2 more answers

Please help need to be in on monday 22 may and im struggling

slavikrds [6]

1 = 84
2 = 40
3 = 54
4 = 18
5 = 35
6 = 21
7 = 33
8 = 26
9 = 30
10 = 8
11 = 27
12= 28
13 = 21
14 = 13
15 = 10

( Task 2 ) Hope this helps :)

5 0

3 years ago

Read 2 more answers

The transitive property of equality states that:

Naily [24]

Answer: If $a=b$ and $b=c$ , then $a=c$

Step-by-step explanation:

Let be "a", "b", and "c" all real numbers, the Transitive property of equalities states that :

If $a=b$ and $b=c$ , then $a=c$

You can observe that if two numbers are equal to the same number, then all this numbers are equal to each other.

For example, applying the Transitive property of equalities to:

$x+3=5$ and $2x+1=5$

You can equate them:

$x+3=2x+1$

And solve for "x":

$3-1=2x-x\\\\x=2$

5 0

4 years ago

Read 2 more answers

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro

VladimirAG [237]

Answer:

Margin of error for a 95% of confidence intervals is 0.261

Step-by-step explanation:

Step1:-

Sample n = 81 business students over a one-week period.

Given the population standard deviation is 1.2 hours

Confidence level of significance = 0.95

Zₐ = 1.96

Margin of error (M.E) = $\frac{Z_{\alpha }S.D }{\sqrt{n} }$

Given n=81 , σ =1.2 and Zₐ = 1.96

Step2:-

 $Margin of error (M.E) = \frac{Z_{\alpha }S.D }{\sqrt{n} }$ 

 $Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }$ 

On calculating , we get

Margin of error = 0.261

Conclusion:-

Margin of error for a 95% of confidence intervals is 0.261

4 0

4 years ago