The sum of 2 sides of a triangle needs to be greater than the length of the 3rd side.
14 + 29 = 43 (this is greater than 41)
14 + 41 = 55 (this is greater than 29)
29 + 41 = 70 (this is greater than 14)
(14, 29,41) can form a triangle.
I believe the answer is b and e
The solutions will lie in all the four quadrants.
y≤2/7x+1
We have the following inequality:
y=2/7x+1
If x=0
y=2/7(0) +1
y=1
If y=0
x=-3.5
So the line passes through the points:
(0,1) and (-3.5,0)
To find the shaded region, let us take a point, namely, the origin and test it in the inequality:
y≤ 2/7x +1
0≤ 2/7(0) +1
0≤ 1 which is true
Since this is true, then the shaded region includes this point. This is shown below and as you can see the solutions exist in all four quadrants.
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Answer:
none of the above
Step-by-step explanation:
The grocer's revenue will be the product of the number of loaves sold (30-2x) and their price (2.50+0.50x).
Revenue will be positive for values of x between those that make these factors be zero. The number of loaves sold will be zero when ...
... 30 -2x = 0
... 15 -x = 0 . . . . . divide by 2
... x = 15 . . . . . . . add x
The price of each loaf will be zero when ...
... 2.50 +0.50x = 0
... 5 + x = 0 . . . . . . . multiply by 2
... x = -5 . . . . . . . . . . subtract 5
Revenue will be positive for any number of increases greater than -5 and less than 15.
_____
D is the best of the offered choices, but it is incorrect in detail. -5 is a number less than 15, but will give zero revenue.