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vivado [14]
3 years ago
10

(giving brainiest) tell how you solved the question

Mathematics
1 answer:
Reptile [31]3 years ago
5 0

Answer:

Step-by-step explanation:

4000

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-2 (3a – 2) = 1/3(7 – 3a)
ahrayia [7]

Answer:

i have no idea. But i will answer because i'm still learning.

Step-by-step explanation:

-2 (3a – 2) = 1/3(7 – 3a)

is whats the question

ok its i'm guessing      -2 (3a – 2) = 1/3(7 – 3a)

-2.15384615385

                         Hope this helps    ;)

7 0
3 years ago
If the mean of the data set is 84 points, find Haruka's final exam score in chemistry,
Pepsi [2]

The answer is 45 because if you divide 84 and 2 you get 42 and then add 3

8 0
3 years ago
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Assume that f is continuous on [-4,4] and differentiable on (-4,4). The table gives some values of f'(x) x: -4, -3, -2, -1, 0, 1
kondaur [170]
f will be increasing on the intervals where f'(x)>0 and decreasing wherever f'(x). Local extrema occur when f'(x)=0 and the sign of f'(x) changes to either side of that point.

f'(x) is positive when x is between -4 and some number between -2 and -1, and also 2 (exclusive) and 4, so you can estimate that f(x) is increasing on the intervals [-4, -2] and (2, 4].

f'(x) is negative when x is between some number between -2 and -1, up to some number less than 2. So f(x) is decreasing on the interval [-1, 1].

You then have two possible cases for extrema occurring. The sign of f'(x) changes for some x between -2 and -1, and again to either side of x=2.
4 0
3 years ago
Which of the following is most likely the next step in the series?
IgorC [24]
A. The hexagon as the series is adding a side each time. So you started with 3, 4, 5...
4 0
3 years ago
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Find the exact value of the composition. arccos (cos pi/2)
Genrish500 [490]
<span>arccos (cos pi/2)=?
</span>cos pi/2=0, arccos (0)=?, we know that cos pi/2=0, so cos^-1 (o)= Pi/2, but cos^-1 (o)=arccos (0), so arccos (cos pi/2)=Pi/2
6 0
3 years ago
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