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2 years ago

Find the range of the data set 145,612,120,349,515,212,590

Mathematics

2 answers:

Westkost [7]2 years ago

6 0

Answer:

The range in the following data set is 470.

Step-by-step explanation:

It's easy, you just have to subtract the highest number from the data set with the lowest number.

So the highest value in this data set would be 590 and the lowest number in the list is 120.

So:

Range: 590 - 120 = 470

~hope this helps~

V125BC [204]2 years ago

5 0

Answer:

the range is 492

Step-by-step explanation:

to find range you have to subtract the smallest number from the largest number so you would subtract 120 from 612 which gets you 492

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2 years ago

Denise walked 4 blocks from her house to the bus stop. She rode the bus 17 blocks to the post office. Later, she came home the s

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2 years ago

Please answer this correctly

Nana76 [90]

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8 0

2 years ago

The endpoints of EF are E(2, 3) and F(8, 11). The midpoint of EF is M.<br> Find the length of EM.

Serga [27]

The midpoint of EF is M. The length of EM is 5

Given :

The endpoints of EF are E(2, 3) and F(8, 11).

M is the midpoint of EF

Lets find out the midpoint M using midpoint formula

$(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )\\E (x_1,y_1) is (2,3)\\F(x_2,y_2) is (8,11)$

Substitute the values inside the formula

$(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )\\\\(\frac{2+8}{2} ,\frac{3+11}{2} )\\\\(5,7)$

Midpoint M is (4,7)

Now to find out length of EM, we use distance formula

$Distance = \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\\mathrm{The\:distance\:between\:}\left(2,\:3\right)\mathrm{\:and\:}\left(5,\:7\right)\\\sqrt{\left(5-2\right)^2+\left(7-3\right)^2}\\\sqrt{3^2+4^2} \\\sqrt{25}\\5$

So, length of EM= 5

Learn more : brainly.com/question/18332427

5 0

2 years ago