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romanna [79]
4 years ago
10

Ummm... halp Dx Please help with 11-29 ILL GIVE BRAINLIEST TANKS FRENS!!! :3

Mathematics
2 answers:
katovenus [111]4 years ago
5 0
18. The answer is 18. Just count down from 29 to 11 and see how many numbers you had to count down from.
Sunny_sXe [5.5K]4 years ago
3 0
11-29 =-18 so there you have it
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234

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Please help me answer this!!
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Angle = 45
Opposite leg = y
Adjacent leg = 5
Tan = opp/ adj
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What’s the vertex of the quadratic function f(x)=(x-8)(x-2)
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To find the vertex we need to represent quadratic function in vertex form.
<span>f(x)=(x-8)(x-2)
</span>f(x)=x²-8x-2x+16=x²-10x+16
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6 0
4 years ago
Random samples of students were compared to see whether or not there was a difference in the proportion favoring the university'
Nimfa-mama [501]

Answer:

There is enough evidence to support the claim that there is a significant difference in the proportion of residents and commuters who prefer the switch.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that there is a significant difference in the proportion of residents and commuters who prefer the switch.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0

The significance level is 0.05.

The sample 1 (residents), of size n1=200 has a proportion of p1=0.4.

p_1=X_1/n_1=80/200=0.4

The sample 2 (conmuters), of size n2=200 has a proportion of p2=0.6.

p_2=X_2/n_2=120/200=0.6

The difference between proportions is (p1-p2)=-0.2.

p_d=p_1-p_2=0.4-0.6=-0.2

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{80+120}{200+200}=\dfrac{200}{400}=0.5

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.5*0.5}{200}+\dfrac{0.5*0.5}{200}}\\\\\\s_{p1-p2}=\sqrt{0.0013+0.0013}=\sqrt{0.0025}=0.05

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.2-0}{0.05}=\dfrac{-0.2}{0.05}=-4

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=2\cdot P(z

As the P-value (0.00008) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that there is a significant difference in the proportion of residents and commuters who prefer the switch.

5 0
4 years ago
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