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arsen [322]
4 years ago
5

100 PTS someone help with my math don't do the graphs thanks

Mathematics
2 answers:
Gnom [1K]4 years ago
8 0

all the equations have two real roots

m_a_m_a [10]4 years ago
7 0

Hello from MrBillDoesMath!

Answer:

All equations have two real roots.


Discussion:

The solutions of the quadratic ax^2 + bx + c = 0  are given by the formula:

x =  (-b +\- sqrt(b^2-4ac) )  /   (2a)

The key element is the discriminant, D, which equals  (b^2-4ac)


For 2)   a = 3, b = 4, c = -4,  D = 4^2 - 4(3)(-4) = 16 + 48 = 64   > 0 so there are two real  solutions

For 4)  D = b^2 - 4ac = (-1)^2 - 4(6)(-1) = 1 + 24 =  25 >0  so there are two real  solutions

For 6), a = -3, b = 12,  c= -11, D = 12^2 - 4(-3)(-11) = 144 - 132 = 12 > 0 so

there are two real  solutions

 

Thank you,

MrB

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