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Orlov [11]
2 years ago
15

I need some help on #18

Mathematics
1 answer:
Nezavi [6.7K]2 years ago
7 0

Answer:

  A. the vertical intercept (often called the y-intercept)

  B. the slope of the line

  C. V(t) = 100t +2000

  D. V(10) = 3000, the value in year 10

  E. see attached

Step-by-step explanation:

<h3>a. </h3>

You are told that year 0 is the year that you made the investment. Then the value in year 0 represents <em>the value of the investment in the year you made the investment</em>. (It is sometimes called the "initial value.")

When the function is graphed, the value in year 0 will be the value on the graph at t=0. If t=0 is the vertical axis (as it usually is), then 2000 is the vertical intercept--the point where the line meets the vertical axis.

__

<h3>b.</h3>

To find the difference between values in consecutive years, subtract one from the other:

  2100 -2000 = 100 . . . . the change in value in consecutive years

On the graph, for each increment of 1 in the value of t, the value of the investment will increase by this amount. That means the slope of the graph (rise/run) is 100/1 = 100. The difference in value in consecutive years is the slope of the graph.

__

<h3>c.</h3>

The equation of the line is ...

  V(t) = (slope) × t + (vertical intercept)

  V(t) = 100t +2000

__

<h3>d.</h3>

V(10) = 100×10 +2000 = 1000 +2000

V(10) = 3000 . . . . . the value of the investment in year 10

__

<h3>e.</h3>

see attached

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