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shusha [124]
3 years ago
11

The base of a triangle is x cm and its height is (x-7) Write down the expression of the triangle

Mathematics
2 answers:
Nata [24]3 years ago
4 0

Step-by-step explanation:

if you mean the area of the triangle then it is S = 1/2*x(x-7)

marishachu [46]3 years ago
4 0

Answer:

Step-by-step explanation:

b= x cm

h = (x - 7) cm

Area of triangle = \frac{1}{2}*x*(x-7)\\\\

                           \frac{x*x-x*7}{2}\\\\=\frac{x^{2}-7x}{2}   square cm

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If x = 4, y = 3, z = -5, then evaluate: z - z + x - y
deff fn [24]
I got -15 as the answer, hope it works
7 0
3 years ago
Read 2 more answers
Please help and explain how to do this
Mnenie [13.5K]

Answer:

  4√3

Step-by-step explanation:

The distance formula applies. It tells you ...

  distance = √((x2 -x1)² +(y2 -y1)²)

Filling in the given values, you have ...

  distance = √((-√32 -(-4√2))² +(2√3 -(-√12))²)

  = √((-4√2+4√2)² +(2√3 +2√3)²)

  = √(0 + (4√3)²)

  distance = 4√3

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We make use of the fact that ...

  a\sqrt{b}=\sqrt{a^2b}\\\\\sqrt{32}=\sqrt{16\cdot 2}=4\sqrt{2}\\\\2\sqrt{3}=\sqrt{2^2\cdot 3}=\sqrt{12}

3 0
3 years ago
Simplify -5^5 ÷ -5^-6
Tpy6a [65]

Answer:

5^11

Step-by-step explanation:

-5^5 ÷ -5^-6

5^5 divide 5^-6

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5 0
3 years ago
After heating up in a teapot, a cup of hot water is poured at a temperature of 204°F.
laila [671]

Answer:

  • Question 1: 0.081 min⁻¹
  • Question 2: 168ºF

Explanation:

The missing equation is:

             T=T_a+(T_0-T_a)e^{-kt}

You are given:

  • Ta = the temperature surrounding the object = 73ºF
  • T₀ = the initial temperature of the object = 204ºF
  • t = 2.5 min
  • T after 2.5 min = 180ºF

Question 1: Find the the value of k.

Substitute the data into the equation and solve for k:

          180\º=73\º+(204\º-73\º)e^{-k\cdot 2.5min}\\ \\ 107\º=131\ºe^{-k\cdot 2.5min}\\\\-k\cdot 2.5min=\ln (107/131)\\\\k=0.081min^{-1}

Question 2: Find the Fahrenheit temperature of the cup of water, to the nearest degree, after 4 minutes.

Subsititute into the formula and compute:

            T=73\ºF+(204\ºF-73\ºF)e^{-0.081min^{-1}\times 4min}\\ \\ T=73\ºF+(131\ºF)(0.72325024)\\\\T=168\ºF

4 0
3 years ago
a certain quantity grows exponeotially over time.the inital quantity at t=0 is 2000.the quantity grows by a factor of 20%. what
kolbaska11 [484]

Answer:

5200

Step-by-step explanation:

2000 x 20% = 400

400 x 8 = 3200

2000 + 3200 =5200

3 0
3 years ago
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