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3 years ago

The base of a triangle is x cm and its height is (x-7) Write down the expression of the triangle

Mathematics

2 answers:

Nata [24]3 years ago

4 0

Step-by-step explanation:

if you mean the area of the triangle then it is S = 1/2*x(x-7)

marishachu [46]3 years ago

4 0

Answer:

Step-by-step explanation:

b= x cm

h = (x - 7) cm

Area of triangle = $\frac{1}{2}*x*(x-7)\\\\$

$\frac{x*x-x*7}{2}\\\\=\frac{x^{2}-7x}{2}$ square cm

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Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

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Let, y'=z

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Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

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Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

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3 years ago

(NEED DONE SOON) The measure of two supplementary angles are 4x - 24 and 4(2x - 3). <br> What is x

Zarrin [17]

Answer:

x = 12

Step-by-step explanation:

A pair of supplementary angles added together MUST equal 180. Therefore, as you are given two angles with the measures of (4x - 24) and 4(2x - 3), they must add together to equal 180. So, we get this equation:

(4x - 24) + 4(2x - 3) = 180

4x - 24 + 8x - 12 = 180 (we distributed 4(2x-3))

12x - 36 = 180

12x = 144

x = 12, -12

Therefore, x is 12 because -12 would mean that (4x-24) and 4(2x-3) are both negative, which is impossible for an angle measure.

5 0

2 years ago