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Ksju [112]
3 years ago
6

Based on a​ poll, among adults who regret getting​ tattoos, 26​% say that they were too young when they got their tattoos. Assum

e that five adults who regret getting tattoos are randomly​ selected, and find the indicated probability. Find the probability that none of the selected adults say that they were too young to get tattoos.
Mathematics
1 answer:
Alik [6]3 years ago
6 0

Step-by-step explanation:

Let's say there were 100 adults.

This would mean there is 26/100 adults who regret getting a tattoo.

This simplifies down to 13/50.

Therefore, 37/50 don't regret getting a tattoo. This means 74% don't regret it. So, you have a 74% chance of that none regret having a tattoo.

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SOLVING EQUATIONS
Andrei [34K]

Answer:

4x + 19 = -21

Step-by-step explanation:

4(-10) + 19 = -21

-40 + 19 = -21

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3 years ago
You can pay $10 for 2 movie tickets assuming the same rate , how much would you pay for 5 movie tickets ?
11Alexandr11 [23.1K]

Answer:

If we assume every 2 movie tickets is $10 then every one ticket would be $5. Assuming this to be true then 5 tickets is $25.

StepByStep Explanation:

movie tickets = t

2t=10

t=5

5t=?

5(5)=?

25=?

?=25


8 0
3 years ago
Erica had 6 coins in her coin collection. she goes to a coin show and buys some coins. how many dose she have now?
rewona [7]
It doesnt say how many she buys at the coin show so we dont know but its going to be more than 6
8 0
3 years ago
Read 2 more answers
Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando
Korolek [52]

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = \frac{7}{13}

For $5 bill, expected value = \frac{1}{13}

For $10 bill, expected value = \frac{3}{13}

For $20 bill, the expected value = \frac{2}{13}

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

6 0
3 years ago
The sample size needed to estimate the difference between two population proportions to within a margin of error E with a signif
devlian [24]

Answer:

n= (z)22E2

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3 0
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