Answer:
<h2>3(cos 336 + i sin 336)</h2>
Step-by-step explanation:
Fifth root of 243 = 3,
Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),
then r^5( cos Ф + i sin Ф )^5 = 243(cos 240 + i sin 240).
Equating equal parts and using de Moivre's theorem:
r^5 =243 and cos 5Ф + i sin 5Ф = cos 240 + i sin 240
r = 3 and 5Ф = 240 +360p so Ф = 48 + 72p
So Ф = 48, 120, 192, 264, 336 for 48 ≤ Ф < 360
So there are 5 distinct solutions given by:
3(cos 48 + i sin 48),
3(cos 120 + i sin 120),
3(cos 192 + i sin 192),
3(cos 264 + i sin 264),
3(cos 336 + i sin 336)
(48a^3 + 32a^2 + 16a) / 4a = ?
48a^3 / 4a = 12a^2
32a^2 / 4a = 8a
16a / 4a = 4
so
(48a^3 + 32a^2 + 16a) / 4a = 12a^2 + 8a + 4
Answer is D. 12a^2 + 8a + 4
Answer: A= (3,-3) . B(4,1). C= (1,0)
Step-by-step explanation:
Answer:
11.33 degrees
Step-by-step explanation:
Answer:
4/11
Step-by-step explanation:
1 blue, 2 green, 3 red, and 5 yellow marbles.= 11 marbles
P( blue or red) = number of blue or red / total
= 4/11
