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Bess [88]
3 years ago
5

Help me pls

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
6 0

Answer:

hope this helps

Step-by-step explanation:

ICE Princess25 [194]3 years ago
4 0
What is under the dropper for me to answer
You might be interested in
Ana ganha 1200,00 reais em seu trabalho, se ela gastar um quinto em comida e dois terços do que sobrar em aluguel, quanto sobra,
lidiya [134]

Answer:

Ana fica com a quantia de 560

Step-by-step explanation:

Dado

Ana ganha = 1200

Ela gasta um quinto com comida e dois terços do que resta com o aluguel

Valor que sobrou com Ana depois de gastar com comida e aluguel

1200 - 1/5 (1200) - 1/3 (1200)

1200 - 240 -400

1200 -640

560

Ana fica com a quantia de 560

3 0
2 years ago
Solve the following 1-step equation for x
shtirl [24]
X/0.5 = 24
X/0.5(0.5) = 24(0.5)
X = 12
5 0
3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 9t + 9 cot(t/2), [π/4, 7π/4]
agasfer [191]

Answer:

the absolute maximum value is 89.96 and

the absolute minimum value is 23.173

Step-by-step explanation:

Here we have cotangent given by the following relation;

cot \theta =\frac{1 }{tan \theta} so that the expression becomes

f(t) = 9t +9/tan(t/2)

Therefore, to look for the point of local extremum, we differentiate, the expression as follows;

f'(t) = \frac{\mathrm{d} \left (9t +9/tan(t/2)  \right )}{\mathrm{d} t} = \frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2}

Equating to 0 and solving gives

\frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2} = 0

t=\frac{4\pi n_1 +\pi }{2} ; t = \frac{4\pi n_2 -\pi }{2}

Where n_i is an integer hence when n₁ = 0 and n₂ = 1 we have t = π/4 and t = 3π/2 respectively

Or we have by chain rule

f'(t) = 9 -(9/2)csc²(t/2)

Equating to zero gives

9 -(9/2)csc²(t/2) = 0

csc²(t/2)  = 2

csc(t/2) = ±√2

The solutions are, in quadrant 1, t/2 = π/4 such that t = π/2 or

in quadrant 2 we have t/2 = π - π/4 so that t = 3π/2

We then evaluate between the given closed interval to find the absolute maximum and absolute minimum as follows;

f(x) for x = π/4, π/2, 3π/2, 7π/2

f(π/4) = 9·π/4 +9/tan(π/8) = 28.7965

f(π/2) = 9·π/2 +9/tan(π/4) = 23.137

f(3π/2) = 9·3π/2 +9/tan(3·π/4) = 33.412

f(7π/2) = 9·7π/2 +9/tan(7π/4) = 89.96

Therefore the absolute maximum value = 89.96 and

the absolute minimum value = 23.173.

7 0
3 years ago
rock is thrown upward with a velocity of 27 meters per second from the top of a 23 meter high cliff and it misses the cliff on t
ahrayia [7]

the rock will be at 11 meters from the ground level after 5.92 seconds

Step-by-step explanation:

The motion of the rock is a free-fall motion, since the rock is acted upon the force of gravity only. Therefore, it is a uniformly accelerated motion, so its position at time t is given by the equation:

y=h+ut+\frac{1}{2}at^2

where

h = 23 m is the initial height

u = 27 m/s is the initial velocity, upward

a=g=-9.8 m/s^2 is the acceleration of gravity, downward

t is the time

We want to find the time t at which the position of the rock is

y = 11 m

Substituting and re-arranging the equation, we find

11=23+27t-4.9t^2\\4.9t^2-27t-12=0

This is a second-order equation, which has solutions:

t=\frac{27\pm \sqrt{(-27)^2-4(4.9)(-12)}}{2(4.9)}=\frac{27\pm \sqrt{964.2}}{9.8}

So

t_1 = -0.41 s

t_2=5.92 s

The first solution is negative so we neglect it: therefore, the rock will be at 11 meters from the ground level after 5.92 seconds.

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

8 0
3 years ago
4. Solve. x² – 81 = 0 (1 point) 0 –9 –9, 9 9
Rudik [331]

x^2 - 81 = 0. Add 81 to each side.

x^2 = 81. Take the square root of each side.

x = 9, -9

5 0
3 years ago
Read 2 more answers
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