The height of the right triangle is 8.08
<h3>Calculating the height of a triangle </h3>
From the question, we are to determine the height of the described right triangle
From the given information,
The angle measure is 30 degrees adjacent to the base
and
The base is 14
Using SOH CAH TOA
Adjacent = 14
Opposite = height of the triangle
Let the height the h
∴ Opposite = h
Thus,
tan 30° = h/14
h = 14 × tan 30°
h = 8.08
Hence, the height of the right triangle is 8.08
Learn more on Calculating height of triangle here: brainly.com/question/10082088
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Answer:
- a) 6.5 seconds
- b) 13 seconds
- c) 679 ft
Step-by-step explanation:
<u>Given function:</u>
a) <u>Maximum height is the vertex.</u> The ball reaches the maximum after:
- h = -208/2(-16) = 6.5 seconds
b) <u>Time the ball was in the air:</u>
Solving we get approximately t = 13 seconds
c) <u>Maximum height is at vertex, we found t above:</u>
- h(6.5) = -16(6.5)^2 + 208*6.5 + 3 = 679 ft
Math helps with science because you'll need to know the math in order to convert units in science.
The first side is 10 inches
the side parallel to this is (10×2)= 20 inches
Height is half the length=1/2×20=10 inches
The area of trapezium is given by:
Area=1/2×h×(a+b)
where a and b are the sides, h is the height. Thus the area will be:
Area=1/2×10×(20+10)
=1/2×10×30
=150 sq. inches
