0<x<1 and 0<y<1
x>0 so x is positive and y>0 so y is also positive.
When you multiply two positive numbers you always get a positive number, so the product of x and y must be positive, or greater than 0.
xy>0 - it must be true
xy<0 - it can't be true
Also when you divide a positive number by a positive number you always get a positive number, so the quotient of x and y must be positive.
x/y<0 - it can't be true
D and E can be true, but don't have to. It depends on the values of x and y. If x>y, then x-y>0 is true and x-y<0 isn't true; if x<y, then x-y>0 isn't true and x-y<0 is true.
Therefore, only A <u>must</u> be true.
Answer:
x = 10
Step-by-step explanation:
In the last step, you can see that the fraction 
has been multiplied by its reciprocal 
, making it cancel out. The reciprocal has been multiplied to both sides, so all you need to do is multiply 
· :
6 · 5 = 30
3 · 1 = 3
<u><em>So now you should have the fraction:</em></u>
x = 
<u><em>But, you can still simplify the fraction by dividing 30 by 3:</em></u>
x = 10
<em>Answer:</em>
<em>There would be 173,535 lionfish after 6 years.</em>
<em>Step-by-step explanation:</em>
<em>Since lionfish are considered an invasive species, with an annual growth rate of 67%, ya scientist estimates there are 8,000 lionfish in a certain bay after the first year, A) to write the explicit equation for f (n) that represents the number of lionfish in the bay after n years; B) determine how many lionfish will be in the bay after 6 years; and C) if scientists remove 1,200 fish per year from the bay after the first year, determine what is the recursive equation for f (n); the following calculations must be performed:</em>
<em></em>
<em>A)</em>
<em>8000 x 1.67 ^ n = f </em>
<em>B)</em>
<em>8000 x 1.67 ^ 6 = X</em>
<em>8000 x 21.691961596369 = X</em>
<em>173,535.692770952 = X </em>
<em>C)</em>
<em>(8000 - 1200 x 1 ^ n) x 1.67 ^ n = f</em>
<em>Therefore, there would be 173,535 lionfish after 6 years.</em>
A. The point estimate of μ1 − μ2 is calculated using the value of x1 - x2, therefore:
μ1 − μ2 = x1 – x2 =
7.82 – 5.99
μ1 − μ2 = 1.83
B. The formula for
confidence interval is given as:
Confidence interval
= (x1 –x2) ± z σ
where z is a value
taken from the standard distribution tables at 99% confidence interval, z =
2.58
and σ is calculated
using the formula:
σ = sqrt [(σ1^2 /
n1) + (σ2^2 / n2)]
σ = sqrt [(2.35^2 /
18) + (3.17^2 / 15)]
σ = 0.988297
Going back to the
confidence interval:
Confidence interval
= 1.83 ± (2.58) (0.988297)
Confidence interval
= 1.83 ± 2.55
Confidence interval
= -0.72, 4.38
