In a football stadium, 43% of the crowd cheering for Team A, and 52% of the crowd is female. 19% of the crowd is cheering for Te am A and female . What is the probability that a randomly selected Person from the crowd are cheering for Team A or female?
1 answer:
P(TeamA) = 0,43 P(Female) = 0,52 P(TeamA and Female) = 0,19 P(TeamA or Female) = ? P(TeamA or Female) = P(TeamA) + P(Female) - P(TeamA and Female) <=> P(TeamA or Female) = 0,43 + 0,52 - 0,19 <=> P(TeamA or Female) = 0,76 or 76%
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Answer:
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Answer:
no
Step-by-step explanation:
Step-by-step explanation:
mL = Undefined
mM = ?
mL × mM = -1
mM = -1 ÷ mL
mM = -1/mL
mM = -1/Undefined
mM = -1/(1/0)
mM = (-1 × 0)/1
mM = 0
Slope of line m is 0
Option → C
The correct answer is B. 0
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