Question

In a football stadium, 43% of the crowd cheering for Team A, and 52% of the crowd is female. 19% of the crowd is cheering for Team A and female . What is the probability that a randomly selected Person from the crowd are cheering for Team A or female?

Answer 1

P(TeamA) = 0,43
P(Female) = 0,52
P(TeamA and Female) = 0,19
P(TeamA or Female) = ?

P(TeamA or Female) = P(TeamA) + P(Female) - P(TeamA and Female) <=>

P(TeamA or Female) = 0,43 + 0,52 - 0,19 <=>

P(TeamA or Female) = 0,76 or 76%