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Jobisdone [24]
3 years ago
6

In a football stadium, 43% of the crowd cheering for Team A, and 52% of the crowd is female. 19% of the crowd is cheering for Te

am A and female . What is the probability that a randomly selected Person from the crowd are cheering for Team A or female?
Mathematics
1 answer:
musickatia [10]3 years ago
4 0
P(TeamA) = 0,43
P(Female) = 0,52
P(TeamA and Female) = 0,19
P(TeamA or Female) = ?

P(TeamA or Female) = P(TeamA) + P(Female) - P(TeamA and Female) <=>

P(TeamA or Female) = 0,43 + 0,52 - 0,19 <=>

P(TeamA or Female) = 0,76 or 76%
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Let f(x)=5(x^2-3)+10. which statement must be true?
Maslowich
Find where the expression
x
−
5
x
2
−
25
x
-
5
x
2
-
25
is undefined.
x
=
−
5
,
x
=
5
x
=
-
5
,
x
=
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Since
x
−
5
x
2
−
25
x
-
5
x
2
-
25
→
→
−
∞
-
∞
as
x
x
→
→
−
5
-
5
from the left and
x
−
5
x
2
−
25
x
-
5
x
2
-
25
→
→
∞
∞
as
x
x
→
→
−
5
-
5
from the right, then
x
=
−
5
x
=
-
5
is a vertical asymptote.
x
=
−
5
x
=
-
5
Consider the rational function
R
(
x
)
=
a
x
n
b
x
m
R
(
x
)
=
a
x
n
b
x
m
where
n
n
is the degree of the numerator and
m
m
is the degree of the denominator.
1. If
n
<
m
n
<
m
, then the x-axis,
y
=
0
y
=
0
, is the horizontal asymptote.
2. If
n
=
m
n
=
m
, then the horizontal asymptote is the line
y
=
a
b
y
=
a
b
.
3. If
n
>
m
n
>
m
, then there is no horizontal asymptote (there is an oblique asymptote).
Find
n
n
and
m
m
.
n
=
1
n
=
1
m
=
2
m
=
2
Since
n
<
m
n
<
m
, the x-axis,
y
=
0
y
=
0
, is the horizontal asymptote.
y
=
0
y
=
0
There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.
No Oblique Asymptotes
This is the set of all asymptotes.
Vertical Asymptotes:
x
=
−
5
x
=
-
5
Horizontal Asymptotes:
y
=
0
y
=
0
No Oblique Asymptotes
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2 1/2

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