Ask question

Ask question

All categories

3 years ago

9

Evaluate

m%20%7D%20m%7B%7D%20" id="TexFormula1" title=" \frac{ {m}^{2} + {m}^{ - 2} + m } m{} " alt=" \frac{ {m}^{2} + {m}^{ - 2} + m } m{} " align="absmiddle" class="latex-formula">
for m=0.5

1 answer:

zysi [14]3 years ago

4 0

Answer:

9.5

Step-by-step explanation:

(0.5^2 + 0.5^-2 + 0.5) / 0.5 = 9.5

Hope this help! :)

You might be interested in

What is the measure of YB

Ivenika [448]

Answer:

what do y and b stand for

Step-by-step explanation:

please elaborate

5 0

3 years ago

Which graph represents exponential decay?

SVEN [57.7K]

EDG Answer: <u>D</u>

<u></u>

<u></u>

you are welcome

3 0

3 years ago

Read 2 more answers

Jasmine buys the magic carpet on sale for $374. She saved $66 off the regular price. What percent was the price discounted?

Furkat [3]

Answer:

15%

Step-by-step explanation:

Let c represent the regular price of the carpet.

Then:

sale price = regular price less discount

$374 = c - $66

Adding $66 to both sides isolates (solves for) c:

$374 + $66 = c = $440. This is the regular price.

$66

---------- = 0.15 This is the fraction of the regular price by

$440 which the regular price is reduced.

Then the percentage of this discount was 0.15(100%) = 15%

8 0

2 years ago

(2,?) is on the line x + 3 = y. Find the other half of the coordinate.

Brut [27]

Sub in 2 for x and solve for y

x + 3 = y
2 + 3 = y
5 = y

so ur points are : (2,5)

4 0

2 years ago

Read 2 more answers

Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ,0)(, plus minus, square root o

Alchen [17]

Answer:

The equation of ellipse centered at the origin

$\frac{x^2}{18} +\frac{y^2}{10} =1$

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)

the focus has x-coordinates so the focus is lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are $c^2=a^2-b^2$

$a^{2} = c^{2} +b^{2}$

$a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}$

$a^{2} =18$

$a=\sqrt{18}$

The equation of ellipse formula

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

we know that $a=\sqrt{18} and b=\sqrt{10}$

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u /> $\frac{x^2}{18} +\frac{y^2}{10} =1$ <u />

8 0

2 years ago

Read 2 more answers