Answer:
The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of
.
Step-by-step explanation:
The formula from the maximum distance of a projectile with initial height h=0, is:

Where
is the initial velocity.
In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is
. The critical points of the function are those who make
:


The critical value inside the interval is
.

The second step is to find the values of the function at the endpoints of the interval:

The biggest value of f is gived by
, therefore
is the absolute maximum.
In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of
.
Answer:
4
Step-by-step explanation:
2x2=4
Using Cavalieri’s Principle, the height of the oblique cylinder with the given volume and base radius is 6cm.
Option A) is the correct answer.
<h3>What is the height of the oblique cylinder?</h3>
From Cavalieri's principle, the volume of an oblique cylinder is expressed as;
V = base area × h
V = πr² × h
Given that;
- Radius r = 9cm
- Volume of the oblique cylinder V = 486πcm³
- Height of the oblique cylinder h = ?
V = πr² × h
486πcm³ = π × ( 9cm )² × h
486πcm³ = π × 81cm² × h
486πcm³ = 81πcm² × h
h = 486πcm³ / 81πcm²
h = 6cm
Using Cavalieri’s Principle, the height of the oblique cylinder with the given volume and base radius is 6cm.
Option A) is the correct answer.
Learn more on volume of cylinder here: brainly.com/question/16788902
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It is C, however I might be wrong so you can visit this website.
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