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djyliett [7]
2 years ago
10

This table shows information about two occupations.

Mathematics
1 answer:
ycow [4]2 years ago
5 0

yes it can be possible to do

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What is the peremeter of this tile 3in 3in 3in 3in I ready
Leokris [45]

Answer:

12 in.

Step-by-step explanation:

The perimeter is calculated by adding all up the sides of a shape.  In this case, the shape is a square, considering that all the sides are the same measurements.  3+3+3+3 can be simplified to 3x4.  This gives you 12 in. as the perimeter.

8 0
3 years ago
Factor x^2-5x-24 i need help to figure this out
Mrac [35]

Answer:

(x-8)(x+3)

Step-by-step explanation:

1) Find out what are the factors of the constant?

2) Which of those add to equal the coefficient before the x value?

In this particular equation, we have the constant being 24. The first two factors that come to mind are 6 and 4, and 8 and 3. Since it is -24, we need one of these numbers to be negative.

Let's look at our "b" value, or the coefficient behind the x value, 5. Looking at our factors and thinking of addition (since one of them must be negative, it will most likely be subtraction instead of addition) I can see that

8+ −3=5

which is one of the factors of -24.

This means that we can factor our equation using these numbers, getting us the following:

(x−3)(x+8)

Hope this helped!

3 0
2 years ago
Solve for t.
STALIN [3.7K]

Step-by-step explanation:

12gt^2=19\qquad\text{divide both sides by}\ 12g\\\\t^2=\dfrac{19}{12g}\to t=\sqrt{\dfrac{19}{12g}}

8 0
2 years ago
4.55 rounded to the nearest hundredth
mylen [45]

Answer:

its still 4.55

Step-by-step explanation:

I dont understand

7 0
3 years ago
Read 2 more answers
Answer this question
Murljashka [212]

Answer:

a = p * q

b = p * s + q * r

c = r * s

Step-by-step explanation:

In the trinomial ax² + bx + c

a is the coefficient of x²

b is the coefficient of x

c is the numerical term

∵ The trinomial is ax² + bx + c

∵ Its factors are (px + r) and (qx + s)

∴ ax² + bx + c = (px + r)(qx + s)

∵ (px + r)(qx + s) = (px)(qx) + (px)(s) + r(qx) + (r)(s)

∴ (px + r)(qx + s) = pqx² + (psx + qrx) + rs

∴ ax² + bx + c = pqx² + (ps + qr)x + rs

→ By comparing the two sides

∵ ax² = pqx² ⇒ divide both sides by x²

∴ a = pq

∵ bx = (ps + qr)x ⇒ Divide both sides by x

∴ b = ps + qr

∴ c = rs

∴ a = p * q

∴ b = p * s + q * r

∴ c = r * s

5 0
2 years ago
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