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prohojiy [21]
3 years ago
15

Helllp fast please someone

Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer: -10

Step-by-step explanation:

-4 - 6 = -10

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Step-by-step explanation:

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6 0
3 years ago
Please help. I’ll mark you as brainliest if correct!!!!
aliya0001 [1]

Answer:

(-∞, -6] U [-2, ∞)

Step-by-step explanation:

To solve this, begin by factoring this quadratic equation into its factored form:

x² + 8x + 12 ≥ 0 becomes (x+6)(x+2) ≥ 0.

x = -6, and x = -2 are the zeros of this parabola. Therefore:

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** Remember, when the '≥' sign is present, the

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8 0
3 years ago
Distribute 3(2x + 5) please help
DIA [1.3K]

Answer: 6x + 15

Step-by-step explanation: The distributive property tells us that if we are given an expression such as 3(2x + 5), we can multiply the 3 by both the 2x and the 5 to get 6x + 15.

My work is also shown below.

6 0
3 years ago
Look in attachment ..answer if u know only pls
timurjin [86]
First of all, you have to understand g<span> is a square-root function. 

</span>Square-root functions are continuous across their entire domain, and their domain is all real x-<span>values for which the expression within the square-root is non-negative. 
</span>
In other words, for any square-root function q and any input c in the domain of q (except for its endpoint), we know that this equality holds:  lim \ q(x)=q(c) 

Let's take \sqrt{x} <span>as an example. 
</span>
The domain of \sqrt x is all real numbers such that x \geq 0.  Since x=0  is the endpoint of the domain, the two-sided limit at that point doesn't exist (you can't approach 0 <span>from the left). 
</span>
<span>However, continuity at an endpoint only demands that the one-sided limit is equal to the function's value: 
</span>
lim \  \sqrt{x} =  \sqrt{0} =0 

In conclusion, the equality lim \ q(x)=q(c) holds for any square-root function q and any real number c  in the domain of q e<span>xcept for its endpoint, where the two-sided limit should be replaced with a one-sided limit. </span>

The input x=-3,  is within the domain of g<span>. 
</span>
Therefore, in order to find  lim \ g(x)  we can simply evaluate g at x-3<span>. 
</span>
g(x) 

\sqrt{7x+22} 

\sqrt{7(-3)+22} 

\sqrt{1} =1
3 0
3 years ago
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