Question

Triangle ABC has vertices at A(0, 5), B(−3, 3), and C(0, −5). Classify the triangle according to the side lengths.

Answer 1

Answer:

Scalene triangle

Step-by-step explanation:

The given triangle has vertices at A(0, 5), B(−3, 3), and C(0, −5).

We use the absolute value method to find the length of AC.

$|AC|=|5--5|=10$ units.

We use the distance formula to get;

$|AB|=\sqrt{(-3-0)^2+(3-5)^2}$

$|AB|=\sqrt{9+4}$

$|AB|=\sqrt{13}$ units

We use the distance formula to find

$|BC|=\sqrt{(-3-0)^2+(-5-3)^2}$

$|BC|=\sqrt{9+64}$

$|BC|=\sqrt{73}$ units.

The three sides of the triangle are not equal in length.

The triangle is scalene