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2 years ago

Solve the inequality 24<5x-1

Mathematics

2 answers:

WARRIOR [948]2 years ago

7 0

Answer:

X>5.

Step-by-step explanation:

First you swap sides, so 5x-1>24. Then simplify to 5x>25, divide 25 by 5 to get 5.

Katena32 [7]2 years ago

5 0

Answer:

5 < x

Step-by-step explanation:

24<5x-1

Add 1 to each side

24+1<5x-1+1

25 < 5x

Divide by 5

25/5 < 5x/5

5 < x

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Step-by-step explanation:

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3 years ago

Equalenlent expression to 24y+16 with distributive propertie

Inessa [10]

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Step-by-step explanation:

To apply the distributive property you need to use parentheses and multiply outside numbers with inside numbers or terms

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Keywords: equivalent expression, distributive property

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3 years ago

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serg [7]

Answer:

$-\frac{x^2y^2}{2}$

Step-by-step explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

$\frac{-3x^3 *2x^3y^4z *3z^2}{4x^3z*3yz*3xyz}$

Multiply the numerators :

$\frac{-18x^6y^4z^3}{4*3*3x^3yyzzz}$

Multiply the denominators :

$\frac{-18x^6y^4z^3}{36x^4y^2z^3}$

Apply the negative rule :

$-\frac{18x^6y^4z^3}{36x^4y^2z^3}$

Cancel the common factor which is 18 :

$-\frac{x^6y^4z^3}{2x^4y^2z^3}$

Apply the addition exponent rule :

$\frac{y^4z^3x^{6-4} }{2y^2z^3}$

Subtract :

$\frac{x^2y^4z^3 }{2y^2z^3}$

Apply the rule for y :

$\frac{x^2y^{4-2} z^3 }{2z^3}$

Subtract :

$\frac{x^2y^2z^3 }{2z^3}$

Cancel the common factor of z^3 :

$-\frac{x^2y^2}{2}$

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3 years ago

True or false and any nonzero integer divided by zero equals zero

kiruha [24]

False, it would equal the nonzero integer
any nonzero integer MULTIPLIED by zero would equal zero

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3 years ago