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julsineya [31]
2 years ago
11

The product of a number and twenty more than that number.

Mathematics
1 answer:
harina [27]2 years ago
4 0

Answer: 20+35=55+20=75

x^{2} x^{2} x^{2} x^{2} x^{2} x^{2} x^{2} x^{2} x^{2} x^{2}

Step-by-step explanation:

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First the first 4 term for 4n-5
likoan [24]

Answer:

-1, 3, 7, 11

Step-by-step explanation:

First, let's find term 1. To find this term, we need to replace n with 1 - what is 4(1) - 5? Well, that's just 4 - 5, or -1. So, our first term is -1. Next, we'll find our second term. To do this, we'll replace n with 2. 4(2) = 8, and then 8 - 5 is equal to 3, so our second term is 3. Let's now find the third term by replacing n with the number 3. 4(3) - 5 is equal to 12 - 5, or 7. So, 7 is our third term. Finally, we'll find the fourth term. 4(4) is equal to 16, and 16 - 5 is equal to 11. So, the fourth and final term is equal to 11.

Hopefully that's helpful! :)

5 0
2 years ago
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3) (5x +41 – 10 = -6<br><br><br> I DONT WANT TO FAIL!!
Mamont248 [21]

Answer:

-74

Step-by-step explanation:

7 0
3 years ago
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How do you solve the equation -7/8k=21
loris [4]
- \frac{7}{8} k = 21

First, simplify \frac{7}{8} k to \frac{7k}{8} / Your problem should look like: -\frac{7k}{8} = 21
Second, multiply both sides by 8. / Your problem should look like: -7k = 167
Third, divide both sides by -7. / Your problem should look like: k = \frac{168}{-7}
Fourth, simplify \frac{168}{-7} to \frac{168}{7} / Your problem should look like: k = - \frac{168}{7}
Fifth, simplify \frac{168}{7} to 24. / Your problem should look like: k = -24

Answer: k = -24

4 0
3 years ago
Help, will mark brainliest!! and give 5 stars this is due 2day!!
Leto [7]

11. brother = ???  

???- 12 = 14

14+12=26

brother is 26.

12. 21.35 - 8.95 = 12.4

cost of colored pencils = $12.40

13. 37- 8 = 29

14. $95  - $73 = $22

6 0
3 years ago
Explain in a full sentence how 4<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B6%7D" id="TexFormula1" title="\frac{2}{6}" al
Luda [366]

Answer:

Step-by-step explanation:

6 0
3 years ago
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